rounding down using floor
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so im using:
floor(10^decimal*(total/AVERAGE_COUNT))/10^decimal;
where:
decimal = 4, AVERAGE_COUNT = 9, total = 8.9289
this entry gives me 0.9920, however the answer should be 0.9921
furthermore, when I just do
total/AVERAGE_COUNT;
it gives me 0.9921 which is correct but i need to use the floor function for the rest of my data.
how do i get around this
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per isakson
2020년 9월 1일
On my R2018b, Win10 this script
%%
format long
decimal = 4; AVERAGE_COUNT = 9; total = 8.9289;
x = floor(10^decimal*(total/AVERAGE_COUNT))/10^decimal
outputs
x =
0.992100000000000
>>
답변 (1개)
Dana
2020년 9월 1일
I'm on R2020a on Windows 10 and I also get 0.9921.
Is it possible that total does not equal exactly 8.9289? For example, if total actually equals 8.92889 (which would usually display as 8.9289 in the command window), then you'll end up with 0.9920.
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