Vectorization time-varying recursive linear function

조회 수: 2 (최근 30일)
Bruno Luong
Bruno Luong 2020년 8월 27일
댓글: David Goodmanson 2020년 8월 29일
I try to vectorize this simple recursive relation (all quantities are scalars)
x_{0} = 0;
x_{n} = x_{n-1}*a_{n} + b_{n} for n=1,2,...,N
In MATLAB code it can be carried out by for loop
% test inputs
b=rand(1,10);
a=0.9+zeros(size(b));
xk=0;
x=zeros(size(b));
for k=1:length(x)
xk = a(k)*xk+b(k);
x(k) = xk;
end
For a(:) constant this can be vectorized by IIR filter
ac = unique(a);
if length(ac)==1
x = filter(1, [1 -ac], b);
end
I would though it could have some time-varying IIR filter that I can use to vectorize the case where a is time-dependent.
But I couldn't find anywhere such stock function. anyone have an idea?

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David Goodmanson
David Goodmanson 2020년 8월 28일
편집: David Goodmanson 2020년 8월 28일
Hi Bruno,
a = rand(1,50);
b = rand(1,50);
% method 1
xk = 0;
x = zeros(1,50);
for k = 1:50
xk = a(k)*xk + b(k);
x(k) = xk;
end
% method 2
cpa = cumprod([1 a(2:end)])
x1 = filter(1,[1 -1],b./cpa).*cpa;
max(abs(x1-x))
ans = 4.4409e-16
  댓글 수: 2
Bruno Luong
Bruno Luong 2020년 8월 28일
편집: Bruno Luong 2020년 8월 28일
Thanks David, very clever workaround.
The problem is that I might have some zeros in A, in that case the filter returns NaN onwards.
David Goodmanson
David Goodmanson 2020년 8월 29일
Hi Bruno,
Also, if one of the a's is nonzero but very small, there are probably going to be numerical accuracy issues. It's unfortunate that Matlab apparently does not have a built-in function for this type of iteration.

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