L=1;
alpha= 10^-3;
T1=800;
T2=200;
x=0:0.01:L;
N=50;
t=0:5:25;
A_0=(T1+T2)/2;
Teaxct=zeros(length(x),length(t));
for m=1:length(x)
for k=1:5:length(t)
for n=1:(N)
A_n(n)=(2*(T1-T2)/pi*(n))*(sin((pi/2)*(n)))*(cos((pi*n*m)/L))*(exp(-1*alpha*((pi*(n))/L)^2*k));
Texact(m,k)=A_0+A_n(n)
end
end
end

댓글 수: 2

KSSV
KSSV 2020년 8월 25일
Why three loops? Type error here in the variable Teaxct.
You can achieve what you want with meshgrid.
Muhammad Umar Khan
Muhammad Umar Khan 2020년 8월 25일
One for each variable

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답변 (1개)

Cris LaPierre
Cris LaPierre 2020년 8월 26일

0 개 추천

In your third loop, the values of m and k do not change. This means the results of each loop are written to the same element of Texact, overwriting the previous value. The result is you only capture the final value in your third loop.
Your code also runs really slow because you are printing out the results of every single interation.
You also have a typo I suspect. You initialize Teaxct but then use Texact in your loops.

댓글 수: 2

Muhammad Umar Khan
Muhammad Umar Khan 2020년 8월 26일
How to resolve it any idea
Fix your typo, add a semicolon to the end of your Texact line, and then describe what your expected output size is. If you want to capture every value, you need to add a third dimension to Texact
Texact(m,k,n)= ...

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