Add time to datetime format

Hi,

I have a datetime format in the following format (MM-dd-yyyy), but it does not have time. How can I add time to it for instance 00:00 (midnight) so I get the format MM-dd-yyyy HH:mm:ss.

Answer 1

[Star Strider]

Try this:

de = ['08/21/2020 (Aug)'; '09/21/2020 (Sep)']
DT = datenum(de, 'mm/dd/yyyy')
DS = datestr([DT + zeros(size(DT,1),1)], 'mm/dd/yyyy HH:MM:SS')

producing:

DS =

  2×19 char array

    '08/21/2020 00:00:00'
    '09/21/2020 00:00:00'

or alternatively just.

    DS = datestr(DT, 'mm/dd/yyyy HH:MM:SS')

producing the same result.

.

Answer 2

[Steven Lord]

A datetime array generally has a time component, even if it's not shown[*].

>> dt = datetime('today')
dt = 

  datetime

   23-Aug-2020

>> dt.Format = 'dd-MMM-yyyy hh:mm:ss a'

dt = 

  datetime

   23-Aug-2020 12:00:00 AM

[*] From the documentation for datetime: "Datetime values later than 144683 years CE or before 140743 BCE display only the year numbers, regardless of the specified Format value."