problem in finding Mean value

조회 수: 3 (최근 30일)
Vennila Gangatharan
Vennila Gangatharan 2013년 1월 6일
편집: Walter Roberson 2017년 6월 26일
Hi,
I want to find mean value of a mammogram only by choosing the values greater than zero. I used for loops with condition but it gives 255 as answer constantly. I don't know what's the mistake i have done.
Code:
[x,y] = size(I);
s = 0;
for i = 1:x
for j = 1:y
if I(i,j) > 0
s = s + I(i,j);
end
end
end
disp('s = ');
disp(s);

채택된 답변

Walter Roberson
Walter Roberson 2013년 1월 6일
Change to
s = s + double(I(i,j));
Question: when you are calculating the mean, are you going to be dividing by the number of values in I, or by the number of non-negative values?
Also are you sure that I will be two-dimensional and not 3 dimensional?
  댓글 수: 1
Vennila Gangatharan
Vennila Gangatharan 2013년 1월 6일
Thank you walter. It works. I am going to divide the sum by no. of non-negative values.
Corrected Code:
[x,y] = size(I);
s = 0;
cnt = 0;
for i = 1:x
for j = 1:y
if I(i,j) > 0
s = s + double(I(i,j));
cnt = cnt + 1;
end
end
end
m = s/cnt;

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추가 답변 (2개)

Image Analyst
Image Analyst 2013년 1월 6일
Why are you doing two loops, which will make it slow? Why not just do:
nonZeroPixels = yourImage > 0;
meanValue = mean(yourImage(nonZeroPixels));
The way above is vectorized, faster, and very MATLABish.

Jan
Jan 2013년 1월 6일
Alternative method without loops:
s = mean(double(I(I > 0)));
  댓글 수: 2
Walter Roberson
Walter Roberson 2013년 1월 6일
mean() works even without the double()
Jan
Jan 2013년 1월 6일
Yes, Walter, because the underlying SUM uses the DOUBLE format as default, when 'native' is not specified. I would prefer to let functions reply the same type as the input as default, therefore I tend to cast more often than needed.

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