Hello everyone i was wondering if u could help me multiply these two increasing variables. They just do not multiply correctly
v0 = (10:1:20);
theta = (30:1:40);
v0_x = v0.*cosd(theta);
v0_y = v0.*sind(theta);

댓글 수: 6

dpb
dpb 2020년 8월 14일
What do you think is incorrect?
It may not be what you were trying to compute, but the result of the two expressions is certainly what would be expected by MATLAB syntax.
Steven Lord
Steven Lord 2020년 8월 14일
What does "do not multiply correctly" mean in this context?
  • Do you receive warning and/or error messages? If so the full and exact text of those messages (all the text displayed in orange and/or red in the Command Window) may be useful in determining what's going on and how to avoid the warning and/or error.
  • Does it do something different than what you expected? If so, what did it do and what did you expect it to do?
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Sara Boznik
Sara Boznik 2020년 8월 14일
I think is correct.
i was expecting the code to create the solutions like this,
10*cosd(30) 11*cosd(30) 12*cosd(30) 13*cosd(30) ....
10*cosd(31) 11*cosd(31) 12*cosd(31) ......
10*cosd(32) 11*cosd(32) ......
10*cosd(33) .......
KSSV
KSSV 2020년 8월 14일
To get this you need to use symbolic tool box.
for v0 = 10:1:20;
for theta = 30:1:40;
v0_x = v0.*cosd(theta)
v0_y = v0.*sind(theta)
end
end
Do you need this?

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 채택된 답변

Shae Morgan
Shae Morgan 2020년 8월 14일
편집: Shae Morgan 2020년 8월 14일

0 개 추천

Is this more what you were looking for?
v0 = (10:1:20);
theta = (30:1:40);
for i= 1:length(v0)
for j = 1:length(theta)
v0_x(i,j)=v0(i)*cosd(theta(j));
v0_y(i,j)=v0(i)*sind(theta(j));
end
end
v0_x
v0_y

댓글 수: 4

yes this is correct, thank you
If you wanted that..simply use:
v0 = (10:1:20);
theta = (30:1:40);
[v0,theta] = meshgrid(v0,theta) ;
v0_x = v0.*cosd(theta);
v0_y = v0.*sind(theta);
i am not familiar with meshgrid
meshgrid() is another great solution here
x=[1 2 3]; %x array
y=[3 2 1]; %y array
[X,Y]=meshgrid(x,y)
%X is a length(y) long set rows of x
%Y is a length(x) long set of columns of y
using these matrices with the point multiplication will give the same outcome. The for-loops feel more intuitive and are visually understandable as you read through the code, but meshgrid requires fewer lines and a little more understanding of what it's doing.
In the end it's preference. I prefer code readability (or familiarizing yourself with new functions so you can improve readability!)

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추가 답변 (1개)

Bruno Luong
Bruno Luong 2020년 8월 14일
편집: Bruno Luong 2020년 8월 14일

0 개 추천

v0 = (10:1:20);
theta = (30:1:40);
v0_x = v0.*cosd(theta.'); % horizontal .* vertical vectors
v0_y = v0.*sind(theta.');

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