Starting off from here:
A=data;
[X,Y,Z]=ndgrid(1:61,1:73,1:61);
x2=linspace(1, 61, 31);
y2=linspace(1, 73, 37);
z2=linspace(1, 61, 31);
[X2 Y2 Z2]=ndgrid(x2, y2, z2);
How are these variables below different? The correlation between data1 and data2 is r=.97.
data1=interpn(X2,Y2,Z2, A, X, Y, Z, 'linear');
data2=griddata(X2,Y2,Z2,A,X,Y,Z,'linear');
Thank you!

답변 (1개)

Bruno Luong
Bruno Luong 2020년 8월 10일

0 개 추천

Mathematical, in short the difference is
  • INTERPN uses tensorial linear function on nd-hypercube that enclose the query point.
  • GRIDDATA uses linear function on nd-simplex the query point

댓글 수: 3

Thanks. Practically, what would be the difference?
Bruno Luong
Bruno Luong 2020년 8월 11일
편집: Bruno Luong 2020년 8월 11일
INTERPN is faster and provides interpolation result more smooth (C1-discontinuouson smaller set) and better symmetric (invariant if you exchange coordinates) than GRIDDATA. If you have initial point on grid use INTERPN.
Use GRIDDATA only when you can't use the other (scattered data).
Thank you!

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도움말 센터File Exchange에서 Interpolation에 대해 자세히 알아보기

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