Resolve normal depth from Manning's equation

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Álvaro Pardo
Álvaro Pardo 2020년 8월 1일
댓글: Álvaro Pardo 2020년 8월 1일
Hello,
I aim to obtain the normal depth of a channel using Mannig's equation. Somehow I don't manage to resolve its value. Here it's the pieco of code that I'm using:
riverSlope=0.0114; % [m/m] - inletSlope, outletSlope or riverSlope
bottom_width=33.5937; % [m] - inlet or outlet bottom width
slope_Rbank=1.1336; % [m/m] - slope_Rbank_in or slope_Rbank_out
slope_Lbank=0.3334; % [m/m] - slope_Lbank_in or slope_Lbank_out
q=10; % [m3/s] - Flow discharge
n=0.04; % [-] - Manning's roughness coefficient
syms y
area=(bottom_width+(y/(2*slope_Rbank))+(y/(2*slope_Lbank)))*y;
wetted_perimeter=bottom_width+y*(sqrt(1+(1/slope_Rbank)^2)+sqrt(1+(1/slope_Lbank)^2));
manning_eqn=@(y)(1/n)*((area/wetted_perimeter)^(2/3))*(riverSlope^(1/2))*area==q;
soly=solve(manning_eqn,y)
I would really appreciate if someone can help to fix it in order to obtain the desired values and avoid the coding of an iteration loop for the manual calculation. Thanks in advance!!
Álvaro

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Alan Stevens
Alan Stevens 2020년 8월 1일
편집: Alan Stevens 2020년 8월 1일
This shoud do it:
depth0 = 1; % Initial guess
depth = fzero(@manningfn, depth0);
function manning = manningfn(y)
riverSlope=0.0114; % [m/m] - inletSlope, outletSlope or riverSlope
bottom_width=33.5937; % [m] - inlet or outlet bottom width
slope_Rbank=1.1336; % [m/m] - slope_Rbank_in or slope_Rbank_out
slope_Lbank=0.3334; % [m/m] - slope_Lbank_in or slope_Lbank_out
q=10; % [m3/s] - Flow discharge
n=0.04; % [-] - Manning's roughness coefficient
area=(bottom_width+(y/(2*slope_Rbank))+(y/(2*slope_Lbank)))*y;
wetted_perimeter=bottom_width+y*(sqrt(1+(1/slope_Rbank)^2)+sqrt(1+(1/slope_Lbank)^2));
manning = (1/n)*((area/wetted_perimeter)^(2/3))*(riverSlope^(1/2))*area-q;
end
  댓글 수: 3
Alan Stevens
Alan Stevens 2020년 8월 1일
Yes, you could do this:
riverSlope=0.0114; % [m/m] - inletSlope, outletSlope or riverSlope
bottom_width=33.5937; % [m] - inlet or outlet bottom width
slope_Rbank=1.1336; % [m/m] - slope_Rbank_in or slope_Rbank_out
slope_Lbank=0.3334; % [m/m] - slope_Lbank_in or slope_Lbank_out
q=10; % [m3/s] - Flow discharge
n=0.04; % [-] - Manning's roughness coefficient
data =[riverSlope; bottom_width; slope_Rbank; slope_Lbank; q; n];
depth0 = 1; % Initial guess
depth = fzero(@manningfn, depth0,[],data);
function manning = manningfn(y, data)
riverSlope=data(1);
bottom_width=data(2);
slope_Rbank=data(3);
slope_Lbank=data(4);
q=data(5);
n=data(6);
area=(bottom_width+(y/(2*slope_Rbank))+(y/(2*slope_Lbank)))*y;
wetted_perimeter=bottom_width+y*(sqrt(1+(1/slope_Rbank)^2)+sqrt(1+(1/slope_Lbank)^2));
manning = (1/n)*((area/wetted_perimeter)^(2/3))*(riverSlope^(1/2))*area-q;
end
Álvaro Pardo
Álvaro Pardo 2020년 8월 1일
Many thanks Alan!

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