replacing Nan with 0

조회 수: 90(최근 30일)
Caroline Prekker
Caroline Prekker 2020년 7월 25일
편집: madhan ravi 2020년 7월 26일
I have an excel file that I need to replace nan with zeros
I am using this piece of code and am getting error : Array indices must be positive integers or logical values
Error in "isnan(auPoints(r,c)) = 0;
I am not sure how to fix it or what I am doing wrong
for r = 4:1:22
for c = 2:1:29
if isnan(auPoints(r,c))
isnan(auPoints(r,c))
end
end
end

답변(3개)

Star Strider
Star Strider 2020년 7월 25일
Try this:
auPoints - fillmissing(auPoints, 'constant',0);
It might be advisable to save the output to a different variable, in order to preserve the original ‘auPoints’ matrix.
See the documentation for fillmissing (R2016b and later versions) for details.

madhan ravi
madhan ravi 2020년 7월 25일
편집: madhan ravi 2020년 7월 25일
auPoints(isnan(auPoints(r, c))) = 0
  댓글 수: 2
madhan ravi
madhan ravi 2020년 7월 25일
Well it’s assumed that c was within the bounds.
Try this: (OBSCURE)
auPoints = subsasgn(auPoints, substruct('()', {isnan(auPoints)}), 0)

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jonas
jonas 2020년 7월 25일
The line does not work because the left part just returns a logical.
isnan(auPoints(r,c)) = 0
It is similar to writing
isnan(NaN) = 0
...which makes no sense but returns the same error message
For this type of basic operation it is better to make use of logical indexing. For example, if you want to replace all your NaNs with zeros, you can write the following
mask = isnan(auPoints);
auPoints(mask) = 0;
The first line returns a logical array (1's and 0's) with the same size as the original array. This array is then used to index the original array. Faster and easier than loops.
More about logical indexing and indexing in general here.
  댓글 수: 2
jonas
jonas 2020년 7월 25일
I don't see how that is possible. The variable mask is literally defined in the first out of the two lines.
Still, you could try the following:
auPoints(isnan(auPoints)) = 0
Note that this is exactly the same, just reduced to one line

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