size Inputs must be scalar

 I want to develop a 3D cubes systematically from 5x5x5 to 15x15x15 with the increments of 1.I developed below code.But there is a problem in the way I am giving the inputs of x,y,z with the increments.





x=5:1:15;
 y=5:1:15;
 z=5:1:15;

B=zeros(x,y,z);
for i =1:x;
    for j=1:y;
        for k=1:z;
            if ((j==1)|(j==y))&((k==1)|(k==z));
                B(i,j,k)=1;
            else B(i,j,k)=0;
              if((i==1)|(i==x))&((k==1)|(k==z));
                B(i,j,k)=1;
            else B(i,j,k)=0;  
                if ((i==1)|(i==x))&((j==1)|(j==y));
                B(i,j,k)=1;
            else B(i,j,k)=0;
               
            end 
        end
    end
    end
    end
end



Error
Error using zeros
Size inputs must be scalar.

Error in  (line 6)
B=zeros(x,y,z);

Answer 1

[madhan ravi]

 B = zeros(numel(x), numel(y), numel(z)); % error is gone but I have no idea what’s going on

[Hege]

x=5:1:15; is not equal to the numel(x).same for the y and z.

could you please tell me why I am getting the error called' Error using zeros. Size inputs must be scalar' for the below first code.

x=5:1:15;

y=5:1:15;

z=5:1:15;

B=zeros(x,y,z);

And If Give the inputs like below no errors.But I want to simplify the code.

x=5,6,7,8,9,10,11,12,13,14,15;

y=5,6,7,8,9,10,11,12,13,14,15;

z=5,6,7,8,9,10,11,12,13,14,15;

B=zeros(x,y,z);

[madhan ravi]

 for x = x
     for y = y
         for z = z
             zeros(x, y, z)
         end
     end
 end 
 doc zeros

[Hege]

Thank you sir.I got the answer.