I would like to run this function.
[dataL_d,Tr] = detrend(dataL,1);
However, the following error always occurs:
Error using detrend. Too many output arguments.
I need the Tr information. If I do not want to output Tr, it works. See command below.
[dataL_d] = detrend(dataL,1);
I would be very happy about an answer.
Best regards,
Christoph

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Star Strider
Star Strider 2020년 7월 15일

1 개 추천

You are asking detrend to remove a linear trend.
To get the slope and intercept of your data, use the polyfit function. There is no specified independent variable value, so use the index vector for that:
P = polyfit((1:numel(dataL)), dataL, 1)
The slope is ‘P(1)’ and the intercept is ‘P(2)’.

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Thank you, this is a simple and good solution.
But it is strange that the above solution ([dataL_d,Tr] = detrend(dataL,1)) is given in https://www.mathworks.com/help/ident/ref/detrend.html (see Remove Linear Trend from a Signal)
That version of detrend is part of System Identification Toolbox and is a method of iddata objects. It is only called if the first input in your call is an iddata object. If the first input is a double precision array MATLAB calls the detrend function included in MATLAB.
My pleasure!
I have not looked at the code for the MATLAB detrend function, however I suspect it uses polyfit (and polyval) to calculate and subtract the trend.
The System Identification Toolbox detrend function (the one you linked to) is a different detrend function altogether. To use it, you must have the System Identification Toolbox, and the argument must be created by the iddata function. They are quite definitely not the same.

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