Matrix Dimension must agree - Vectorization

조회 수: 1 (최근 30일)
Toan Nguyen
Toan Nguyen 2020년 7월 13일
답변: Mahesh Taparia 2020년 7월 16일
Hi there,
I created a function called Fx which takes an single number as input and produce a 1 single number as output.
I tried to run:
n = 1:10;
r = Fx(n);
What I expected is an array of r 1x10, each contains the result of Fx of n from 1 to 10.
However, I got "Matrix dimensions must agree" instead. This does not make sense to me. I tried to run it with for loop and it worked just fine.
for n = 1:10
r(n) = Fxl(n);
end
The array involved in the calculation of Fx is 115824. So I tried with array n of 1x115824 then the code only return the result of n(1,1) only.
Does anyone know what's going on here?
If so, please let me know.
Thank you
  댓글 수: 9
madhan ravi
madhan ravi 2020년 7월 13일
“I tried to run it with for loop and it worked just fine.”
What is the problem then??
Toan Nguyen
Toan Nguyen 2020년 7월 13일
I'm sorry that I did not clarify the objective.
For loop is slow with 100 runs already and my aim is around 100k.
From what I heard, vectorization is faster. Thus, that's what I'm trying to do

댓글을 달려면 로그인하십시오.

답변 (1개)

Mahesh Taparia
Mahesh Taparia 2020년 7월 16일
Hi
It seems you want to apply a function on each element of an array without applying for loop. In this case, create that function according to the input, i.e, give array as the function input and apply the whole computation on that array which finally returns a vector as functional output.

카테고리

Help CenterFile Exchange에서 Loops and Conditional Statements에 대해 자세히 알아보기

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by