i=1, 2, 3,,, However, when (a-i)> 0 is calculated.

i=1, 2, 3,,,

However, when (a-i)> 0 is calculated.

N, a is any positive integer,

station(2+i)=(a-(a-i))*N

I am trying to make a do statement, but I get an error

I am wondering how I should write the code to run it.

for example.

 if a=4
    i=1 station(3)=(4-(4-1))*N
    i=2 station(4)=(4-(4-2))*N
    i=3 station(5)=(4-(4-3))*N
    i=4 station(6)=(4-(4-4))*N %->This case is not considered. Because  (a-i) <= 0  (when (a-i)> 0 is calculated.)

Answer 1

[madhan ravi]

clear station
a = 4
ii = 1:a-1;
N = 2; % any nunber
station(ii+2) = (4-(4-ii))*N

Answer 2

[Walter Roberson]

for i = 1 : a - 1
 station(i+2) = (4-(4-i))*N;
end

Answer 3

[John D'Errico]

Or, with no loop at all, and no test required. Just

i = 1:a-1;
station(i+2) = (4-(4-i))*N;

This will define the entire vector at once, leaving station(1) and station(2) as zero. But then you never said what they were anyway.