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handle character minus character

조회 수: 7 (최근 30일)
Ancalagon8
Ancalagon8 2020년 7월 10일
댓글: madhan ravi 2020년 7월 10일
I have two characters which contain '18:29:42.835' and '18:29:49.425'. How is it possible to subtrack t2-t1 so as to find duration?

채택된 답변

madhan ravi
madhan ravi 2020년 7월 10일
f = @(x) str2double(regexp(x,':','split'));
t1 = num2cell(f(t1)); % where t1 & 2 are your char arrays
t2 = num2cell(f(t2));
Wanted = duration(t2{:})-duration(t1{:})
  댓글 수: 2
Ancalagon8
Ancalagon8 2020년 7월 10일
thanks it worked! But it only shows me seconds and i need also the difference in decimals..
madhan ravi
madhan ravi 2020년 7월 10일
f = @(x) str2double(regexp(x,'\D','split'));
t1 = num2cell(f(t1));
t2 = num2cell(f(t2));
Wanted = duration(t2{:})-duration(t1{:});
Wanted.Format = 'hh:mm:ss.SSSS'

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추가 답변 (1개)

Walter Roberson
Walter Roberson 2020년 7월 10일
If you have a recent enough MATLAB version, pass the character vectors to duration() and then subtract one from the other.
If your MATLAB is a bit older, then you will need to split the vectors at the colons, then str2double() to get the individual components, and pass those to duration.
Or you could use sscanf() with a format of '%f:%f:%f' to get the numeric components and pass those to duration()

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