Substitute for eval function

% load('DATA_FC');
% load('VARS');
% 
% t=1;
% k=1;
%     for j=1:1:13428
%       for i=1:1:1001
%         temp=[raw{k,1} '(i,t)=DATA_FC(i,j)'];        
% %         eval(temp);
%       end      
%       if rem(t,36)==0
%           k=k+1;
%           t=1;
%       else
%       t=t+1;
%       end      
%     end

I have data in DATA_FC --> which is of dimension 1001*13428

I have variables in VARS (373 variables, A1,A2....A373).

I want that these 373 variables each should contain the data 1001*36 dimension (data to be picked from DATA_FC)

Eval functions is very slow.

Can anyone please suggest a fast alternative code to this problem.

[Walter Roberson]

http://www.mathworks.com/matlabcentral/answers/304528-tutorial-why-variables-should-not-be-named-dynamically-eval

[Stephen23]

"Can anyone please suggest a fast alternative code to this problem."

load into output variables and access their fields:

https://www.mathworks.com/help/matlab/ref/fieldnames.html

https://www.mathworks.com/help/matlab/matlab_prog/generate-field-names-from-variables.html

Answer 1

[KSSV]

It is not adivsed to use eval. You can reshape your data into what you want. Check below:

DATA_FC = rand(1001,13428) ;  % random data for demo
[r,c] = size(DATA_FC);        % get dimensions 
nvars  = 373;                 % number of variables needed 
A   = reshape(DATA_FC,[r,c/nvars,nvars]);   % reshape 

Now you can access your required variables...A1 will be A(:,:,1), A10 will be A(:,:,10)..etc.

[Ninad Pimpalkhare]

Thank you that helped a lot. I had to only use eval function now to assign the particular variable name. Done in 1 min.