Create all unique combination with a vector array

조회 수: 18 (최근 30일)
cht
cht 2020년 7월 8일
댓글: Bas van Dorp 2021년 4월 28일
Hello,
let`s say I have a vector a=[1 1 0 0 0]. I want to build all possible combinations with the values within that vector. I`m looking for such result:
[1 0 1 0 0]
[1 0 0 1 0]
[1 0 0 0 1]
[0 1 1 0 0]
[0 1 0 1 0]
and so on till [ 0 0 0 1 1]
With the function perms there is quite a lot of redundancy and the order of the sigles arrays is not the one I would like
  댓글 수: 2
madhan ravi
madhan ravi 2020년 7월 8일
What do you mean mean by lots of redundancies, you are the ones asking for unique combinations?
cht
cht 2020년 7월 8일
If I use perms, they are a lot of combination that are the same. This is the meaning of redundancy.

댓글을 달려면 로그인하십시오.

채택된 답변

Bruno Luong
Bruno Luong 2020년 7월 9일
Try this, no redundancy created. However the number of combinations still grow very quick so be awared. Where as it gives the order you expect, who knows since you never specify the order you want.
function c = vperm(v)
[u,~,J] = unique(v);
n = accumarray(J(:),1);
c = vpengine(u,n).';
end
function c = vpengine(u,n)
if length(u)==1
c = u + zeros(n,1);
else
k = n(1);
i = nchoosek(1:sum(n),k);
p = size(i,1);
j = repmat((1:p)',1,k);
c = accumarray([i(:),j(:)],1);
d = vpengine(u(2:end),n(2:end));
c = repelem(c,1,size(d,2));
b = c==0;
d = repmat(d,1,p);
c(b) = d(:);
c(~b) = u(1);
end
end
Test:
>> vperm([1 1 0 0 0])
ans =
0 0 0 1 1
0 0 1 0 1
0 0 1 1 0
0 1 0 0 1
0 1 0 1 0
0 1 1 0 0
1 0 0 0 1
1 0 0 1 0
1 0 1 0 0
1 1 0 0 0
  댓글 수: 1
Bas van Dorp
Bas van Dorp 2021년 4월 28일
Nice work!
I first used unique(perms(a),'rows'). For my purposes that does the same, but it gets very slow and runs out of memory when a is too long. This was limiting my program but with your script it works!
Thanks for this.

댓글을 달려면 로그인하십시오.

추가 답변 (0개)

카테고리

Help CenterFile Exchange에서 Loops and Conditional Statements에 대해 자세히 알아보기

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by