How to compute arccos for a matrix?

조회 수: 13 (최근 30일)
Omar B.
Omar B. 2020년 7월 4일
댓글: Walter Roberson 2020년 7월 7일
I would like to compute the arccos for a matrix. I know when I want to find log(), exp(), and sqrt () for a matrix , we use logm(A), expm(A) and sqrtm(A) where A is a matrix.
I want to find the following:
x=acos(sqrtm(A)\eye(n))
so, Is it correct to compute it like this ? Or we need to use arccosm(sqrtm(A)\eye(n))? Thank you.
  댓글 수: 2
Walter Roberson
Walter Roberson 2020년 7월 4일
There are no trig matrix functions in MATLAB, except the ones that work element by element.
Omar B.
Omar B. 2020년 7월 4일
So, is it correct to compute the following?
x=acos(sqrtm(A)\eye(n))

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답변 (1개)

Walter Roberson
Walter Roberson 2020년 7월 5일
It depends what you are trying to calculate.
And so we could potentially generalize that for matrices, there might be some meaning to
arccosm = @(z) 1i * logm(z + sqrtm(z^2 - 1))
I am having difficulty thinking of a context in which there could be physical meaning for this.
If we substitute in 1/sqrtm(A) then
1i*logm(sqrtm(A\eye(n) - 1) + sqrtm(A)\eye(m))
But is there a meaning for this??
  댓글 수: 11
Omar B.
Omar B. 2020년 7월 7일
I really appreciate your help. I am really confused about that. I want to evaluat matrix A at the following function
f(x)=arccos(1/sqrt(x))/sqrt(x)
Walter Roberson
Walter Roberson 2020년 7월 7일
f1 = @(x) acos(sqrtm(x)^(-1)) * sqrtm(x)^(-1);
f2 = @(x) acos(sqrtm(x)/eye(size(x,1))) / sqrtm(x);
f3 = @(x) acos(1./sqrt(x)) ./ sqrt(x);
f1(A)
f2(A)
f3(A)
Try them all and decide which one is the right solution for you.

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