How do I define a structure that has an element which is an array?
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How do I define a structure that has an element which is an array and for which there are sub elements. I have composed a simple example below of what I want to do along with a failed attempt at the needed assert statements.
function y = payroll(personnel)
%#codegen
% Specify the class of the input as struct.
assert(isstruct(personnel));
% Specify the class and size of the fields r and i
% in the order in which you defined them.
assert(isa(personnel.num_employees,'int32'));
assert(isa(personnel.employee,'int32'));
assert(all(size(personnel.employee) == [5 1]));
assert(isa(personnel.employee(1).salary,'int32'));
for i = personnel.num_employees
total_payroll = total_payroll + personnel.name(i).salary;
end
y = total_payroll;
end
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채택된 답변
Fred Smith
2012년 12월 7일
This line seems wrong:
assert(isa(personnel.employee,'int32'));
In your code employee is supposed to be a struct with sub-field name and salary? Once you make it a struct, you then also need to set its class and size of the fields name and salary.
-Fred
추가 답변 (3개)
John Petersen
2012년 12월 6일
편집: John Petersen
2012년 12월 6일
1. Find out which assertion fails. The code looks fine.
2. Replace the 'for' loop with
y = sum([personnel.name.salary]);
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Jan
2012년 12월 7일
This will crash, if the personnel.employee has more than 2 dimensions:
all(size(personnel.employee) == [5 1])
Better:
isequal(size(personnel.employee), [5 1])
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Sean de Wolski
2012년 12월 7일
total_payroll = total_payroll + personnel.name(i).salary;
total_payroll is never defined before being used for the first time!
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