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How can I save UIAxes as an image when button is pushed in app designer?

조회 수: 47 (최근 30일)
Yaren Sever
Yaren Sever 2020년 7월 3일
편집: Image Analyst 2022년 1월 5일
How can I save UIAxes as an image when button is pushed in app designer?
newfigure = figure;
copyobj(app.UIAxes, newfigure);
hgsave(newfigure, 'testFIgure.fig');
I tried this but it gives me an error.
  댓글 수: 3
Yaren Sever
Yaren Sever 2020년 7월 4일
2020 release. I solved the problem but now when I push the button, XLabel, YLabel and Title of the UIAxes dissappears. Do you have any idea about this?
% Create new axis
newAxes = axes;
% Copy all objects from UIAxes to new axis
newAxes.Title= app.UIAxes.Title;
newAxes.XLabel = app.UIAxes.XLabel;
newAxes.YLabel = app.UIAxes.YLabel;
copyobj(app.UIAxes.Children, newAxes)
fig2Save = ancestor(newAxes, 'figure');
fig2Save.Visible='off';
%dialog box,save as
filter = {'*.jpg';'*.png'}
[filename, pathname] = uiputfile(filter);
newfilename = fullfile(pathname, filename);
saveas(fig2Save, newfilename);
Yaren Sever
Yaren Sever 2020년 7월 4일
I solved whole problem:
figure;
% Create new axis
newAxes = axes;
% Copy all objects from UIAxes to new axis
newAxes.Title= app.UIAxes.Title;
newAxes.XLabel = app.UIAxes.XLabel;
newAxes.YLabel = app.UIAxes.YLabel;
copyobj(app.UIAxes.Children, newAxes)
%in order to keep titles and labels on uiaxes
xlabel(app.UIAxes, newAxes.XLabel.String);
ylabel(app.UIAxes, newAxes.YLabel.String);
title(app.UIAxes, newAxes.Title.String);
fig2Save = ancestor(newAxes, 'figure');
fig2Save.Visible='off';
%saveas(fig2Save,'myfigg.png')
%close(fig2Save);
%dialog box,save as
filter = {'*.jpg';'*.png'}
[filename, pathname] = uiputfile(filter);
newfilename = fullfile(pathname, filename);
saveas(fig2Save, newfilename);

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답변 (2개)

Image Analyst
Image Analyst 2020년 7월 3일
Try exportgraphics().
  댓글 수: 3
Yaren Sever
Yaren Sever 2020년 7월 4일
2020 release. I solved the problem but now when I push the button, XLabel, YLabel and Title of the UIAxes dissappears. Do you have any idea about this?
% Create new axis
newAxes = axes;
% Copy all objects from UIAxes to new axis
newAxes.Title= app.UIAxes.Title;
newAxes.XLabel = app.UIAxes.XLabel;
newAxes.YLabel = app.UIAxes.YLabel;
copyobj(app.UIAxes.Children, newAxes)
fig2Save = ancestor(newAxes, 'figure');
fig2Save.Visible='off';
%dialog box,save as
filter = {'*.jpg';'*.png'}
[filename, pathname] = uiputfile(filter);
newfilename = fullfile(pathname, filename);
saveas(fig2Save, newfilename);

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Adam Danz
Adam Danz 2020년 9월 24일
The code you shared shows that you're exporting the children of a UIAxes onto a regular axis.
That can be done with copyUIAxes() from the file exchange, even on Matlab releases prior to 2020. That function avoids the problem of disappearing axis labels.
  댓글 수: 2
zsh fardi
zsh fardi 2022년 1월 5일
편집: Image Analyst 2022년 1월 5일
Hi. Why is copyUIAxes() undefined in Matlab R2021a?
Image Analyst
Image Analyst 2022년 1월 5일
편집: Image Analyst 2022년 1월 5일
@zsh fardi Because it's a third party function written by Adam. It's not part of base MATLAB. You have to download it, and if it's not in your current folder, use the "Set Path" button on the Home tab of the tool ribbon to add its folder to the path.

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