Position and extraction of row

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Alexandra Philip
Alexandra Philip 2020년 7월 1일
댓글: Star Strider 2020년 7월 2일
I am having some trouble find the position of the row within a table. I first did:
[rows,columns]=find(strcmp(mergetable1{:,1},AccelSN),1) to try to find where the user input variable(AccelSN) matches a number in the 1st column and then to find the row where the values match.
I use BIA0=mergetable1{rows,2} to extract the value in the same row extracted in the previous line and in the 2nd column.
I get an output of:
rows =
[]
and
BIA0 =
0×1 empty double column vector
Any suggestions to obtain the row and get an extracted value from the column of that row?

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Star Strider
Star Strider 2020년 7월 1일
It would definitely help to see what ‘mergetable1’ is, and how you are getting ‘AccelSN’.
If ‘AccelSN’ is read as a string (for example from inputdlg), use the str2double function to get it as a number, since the first column of ‘mergetable1’ is apparently numeric.
For example:
mergetable1 = array2table(randi(9, 10, 3)) % Create Table (To Test Code)
AccelSN = {'4'}; % From ‘inputdlg’
AccelSN = str2double(AccelSN); % Convert To Numeric
BIA0 = mergetable1{AccelSN == mergetable1{:,1},2}
Col_3 = mergetable1{AccelSN == mergetable1{:,1},3}
Please test that with your table and code, since I cannot.
.
  댓글 수: 3
Alexandra Philip
Alexandra Philip 2020년 7월 1일
I was able to get the code to work. Thank you.
Star Strider
Star Strider 2020년 7월 2일
As always, my pleasure!
(It would have helped significantly to have your table and code.)

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