Calculate radius from scatter plot
이전 댓글 표시
Hi,
I need to calculate the radius of a circle, ignoring all surrounding particles (image attached). The circle itself consists of many particles (over 100,000). Note that the center of the circle is not at the origin.
Thanks.
EDIT: here is how I solved it:
posn=normal(poscm); %poscm is the coordinates matrix
[k,edges]=histcounts(posn,1e5);
[~,imaxk]=max(k);
R=edges(imaxk+find(k(imaxk:end)==0,1)); %find the first zero value after the maximum
댓글 수: 5
Adam Danz
2020년 6월 22일
I assume you're computing the radius based on a set of coordinates, or are you computing it based on the image?
yonatan s
2020년 6월 22일
Some ideas off the top of my head.....
There are several things you could try to get rid of the outliers. For example, you could try matlab's isoutlier function.
Since the signal to noise ratio looks very high, you could try fitting the circle directly without removing any of the outliers. There may be a file on the file exchange that fits a circle to a cluster of dots but avoid using circle-fitting algorithms that use least squares or that fit a circle according to dots along a circumference.
It may be helpful to see a distribution of point distances which may give you an approximate diameter estimate. pdist() would give you the distance between all points but it also may reach memory capacity since you have very many points.
You could also try a clustering technique. I wonder if kmeans() would be sufficient to find the center of the circle. Again, your SNR is very high so the outliers may not matter.
You might be able to use an image processing approach such as regionprops, too.
yonatan s
2020년 6월 23일
Adam Danz
2020년 6월 23일
If you're still looking for a solution, attach the fig file containing the data, or attach a mat file containing the (x,y) coordinates.
답변 (3개)
Matt J
2020년 6월 22일
1 개 추천
You could try using clusterdata to find the big concentration of points. Then minboundcircle from the File Exchange to get the radius,
darova
2020년 6월 23일
Try density function hist3
r = rand(500,1)/5;
t = rand(500,1)*2*pi;
x = [rand(50,1); r.*cos(t)+0.5];
y = [rand(50,1); r.*sin(t)+0.5];
n = 20;
k = hist3([x y],[n n]);
k(k<2) = nan;
pcolor((0:n-1)/n,(0:n-1)/n,k)
hold on
plot(x,y,'.r')
hold off

카테고리
도움말 센터 및 File Exchange에서 k-Means and k-Medoids Clustering에 대해 자세히 알아보기
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