no use of for loop

조회 수: 3 (최근 30일)
Rica
Rica 2012년 11월 29일
Hi!
n=[0:0.01:0.5];
f=[2:0.01:3];
for k=1:length(n)
for l=1:length(f)
beta=n(k).*Dc/Dw
omega=2e9*pi*f(l);
epsilon=3./(1+j*omega*tau);
epsilon_k(k,l)=(beta*(epsilon)+(1-beta)(epsilon_cc));
end
end
is there any advice to programm this without using for loops?
Thank you
EDIT CORRECTED PROGRAM:
Hi sorry. here is the corrected program.
n=[0:0.01:0.5];
f=[2:0.01:3];
epsilon_cc=2
for k=1:length(n)
for l=1:length(f)
beta=n(k);
omega=2e9*pi*f(l);
epsilon=3./(1+j*omega*tau);
epsilon_k(k,l)=(beta*(epsilon)+(1-beta)*(epsilon_cc))
end
end
thank you for your help!
  댓글 수: 2
Azzi Abdelmalek
Azzi Abdelmalek 2012년 11월 29일
What are sizes of Dc , omega
Wayne King
Wayne King 2012년 11월 29일
You should make your post so that people can actually execute your code. You do not give Dc, or Dw, and what is this line
epsilon_k(k,l)=(beta*(epsilon)+(1-beta)(epsilon_cc));
are you multiplying 1-beta and epsilon_cc?

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Jan
Jan 2012년 11월 29일
편집: Jan 2012년 11월 29일
The variable "epsilon" does not change its value inside the loop, so move its calculation out of the loop.
"beta" does not change its value inside the inner loop, so move to the outer loop.
The variables "j", "epsilon_cc", "Dc" and "Dw" are not defined in the code snippet. We cannot guess their values or if they are functions.
The expression "(1-beta)(epsilon_cc)" is not valid in Matlab. Perhapos you forgot a "*".
Please cleanup the code at first.

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