Empty sym: 0-by-1

조회 수: 2 (최근 30일)
Nikos Gavalakis
Nikos Gavalakis 2020년 6월 17일
댓글: Star Strider 2020년 6월 17일
Hello, I'm new to matlab so any help would be appreciated! I needed matlab to solve some equation systems for my finite element class.
The method I used to use worked until this 4x4 system. I'm not sure what's the best way to solve this and with my way i get "Empty sym: 0-by-1" as an answer.
(the "P(u3)" is just a symbol, not a multiplication. P(u3)=p....and also E*A/L=5*10^7)
syms u2 v2 u3 p
e1= (5*10^7)*(2/4*u2 - 1/4*u3 + 3/4*u3)==0;
e2= (5*10^7)*(6/4*v2+sqrt(3)/4*u3-3*sqrt(3)/4*u3)==19613;
e3= (5*10^7)*(-1/4*u2+sqrt(3)/4*v2+1/4*u3-3/4*u3)==p;
e4= (5*10^7)*(sqrt(3)/4*u2-3/4*v2-sqrt(3)/4*u3+3*sqrt(3)/4*u3)==sqrt(3)*p;
result = solve(e1,e2,e3,e4)
result =
struct with fields:
p: [0×1 sym]
u2: [0×1 sym]
u3: [0×1 sym]
v2: [0×1 sym]
vpa(result.p)
ans =
Empty sym: 0-by-1

채택된 답변

Star Strider
Star Strider 2020년 6월 17일
Your error was in not leaving it in the original matrix form.
This works, however I am confused by your notation, so this may need to be corrected:
syms u2 v2 u3 p
Mtx = 5E+7 * [2/4 0 -1/4 +3/4;
0 6/4 sqrt(3)/4 -3*sqrt(3)/4;
-1/4 +sqrt(3)/4 +1/4 -3/4;
sqrt(3)/4 -3/4 -sqrt(3)/4 +3*sqrt(3)/4];
Vct = [0; 19613; p; sqrt(3)*p];
V = [u2; v2; u3; p];
S = vpasolve(Mtx * V == Vct);
Sp = S.p
Su2 = S.u2
Su3 = S.u3
Sv2 = S.v2
producing:
Sp =
-5661.785414808065059658960697873
Su2 =
17115934194006.985529996788305132
Su3 =
34231868371028.614815569381431287
Sv2 =
-9881889214341.853390449609171597
.
  댓글 수: 2
Nikos Gavalakis
Nikos Gavalakis 2020년 6월 17일
Thank you very much m8!! I'm going to solve matrices this way from now on.
Btw I might have done something else wrong because i wasnt expecting u2,v2,u3 to be such large numbers :(
Star Strider
Star Strider 2020년 6월 17일
As always, my pleasure!
Since the matrix is multiplied by 5E+7, the large numbers do not surpise me.

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