필터 지우기
필터 지우기

Manual Weighted Least Squares Estimation

조회 수: 7 (최근 30일)
Chris Herdelin
Chris Herdelin 2020년 6월 17일
댓글: Chris Herdelin 2020년 6월 19일
I have estimated WLS manually by dividing each of the coefficients by income^0.5. My question is, when I do that, does it automatically divde the constant by income^0.5? If not, how would I add 1/income^0.5 for the constant? Would I just create a variable for 1/income^2 and then add it to the matrix where I have all of my coefficents? Any help you could give would be greatly appreciated!

답변 (1개)

Ajit Kasturi
Ajit Kasturi 2020년 6월 18일
Assuming that you are asking whether division of each element of the matrix works, Yes it does. You can divide/add the constant (in your case it is 1/income^2) element-wise to a matrix as shown below.
Income = 2;
x= [1 2 3; 2 3 4; 4 5 6];
c= income^2;
Y=x/c;
For more information, refer the following link:
  댓글 수: 2
Chris Herdelin
Chris Herdelin 2020년 6월 18일
Thanks so much! Ok. That makes sense. Then how do I include the constatn when performing the regression mdl = fitlm(X,Y)? Doesn't the regression automatically calculate the constant? How do I incorporate the constant 1/income^2 into the regression equation? Thanks again!
Chris Herdelin
Chris Herdelin 2020년 6월 19일
Income = 2;
x= [1 2 3; 2 3 4; 4 5 6];
c= income^2;
Y=x/c;
Error using ^ (line 51)
Incorrect dimensions for raising a matrix to a power.
Check that the matrix is square and the power is a
scalar. To perform elementwise matrix powers, use
'.^'.

댓글을 달려면 로그인하십시오.

카테고리

Help CenterFile Exchange에서 Gaussian Process Regression에 대해 자세히 알아보기

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by