Dear all,
I am a beginner in Matlab and I need your help. Here is my problem: I have a cloud of data obtained by measurement. Thanks to those datas I have made a matrix(49x49) which allowed me to plot a paraboloid. I would like to fit this 3d curve based on data, but I don't know how to start. Could you please help me to find a way to solve this problem?
Sincerely,
Elza

 채택된 답변

Andrew Newell
Andrew Newell 2011년 4월 14일
편집: John Kelly 2014년 6월 12일

1 개 추천

If you have the Curve Fitting Toolbox, you could try interactive surface fitting.
EDIT: If you don't have it, you could try polyfitn, which you can download from the File Exchange.

추가 답변 (4개)

Elza
Elza 2011년 4월 14일

1 개 추천

Many thanks for your answer. Actually I don't have this tool. Do you know an other way to do it?
Thanks a million.
Elza
Jarrod Rivituso
Jarrod Rivituso 2011년 4월 14일

0 개 추천

Could you cast it as a linear regression problem and then solve the equations using backslash? Some details:
Say we are trying to fit to an equation of the form
z = c1*f1(x,y) + c2*f2(x,y) + ...
where f1 and f2 are the basis functions of the linear equation, and c1,c2,etc. are the coefficients. You could write this as a matrix equation...
z = [f1(x,y) , f2(x,y) , ...] * [c1 ; c2 ; ...]
Here's an example in MATLAB with some data I made up...
%Define grid of x,y values
x = -1:0.01:1;
y = -1:0.01:1;
[X,Y] = meshgrid(x,y);
%Make up some data
data = X.^2 + 3*Y.^2 + 0.01*rand(size(X));
%Set the basis functions
f1 = ones(size(X));
f2 = Y.^2;
f3 = X.^2;
%Write as matrix equation
A = [f1(:),f2(:),f3(:)];
y = data(:);
%Solve for coefficients
coeffs = A\y
Elza
Elza 2011년 4월 20일

0 개 추천

Thanks for your help Jarrod, I'll try that and let you know if it works for me.
Many thanks
Sonali
Sonali 2023년 8월 27일

0 개 추천

Rt = 30.5;
area_ratio = 31.4754;
theta = 50;
theta_exit = 16.5;
theta_n = theta*pi/180;
k = 0.8;
Ln = k*(sqrt(area_ratio)-1)*Rt/tand(theta_exit);
% FIRST CURVE (FC)
% Angles for First Curve
Angle_FC = -(pi+(45*pi/180));
FC_step = (-pi/2-Angle_FC)/100;
theta_FC = (-3*pi/4):FC_step:(-pi/2);
% Coordinates for First Curve
x_FC = cos(theta_FC)*1.5*Rt;
y_FC = sin(theta_FC)*1.5*Rt+(1.5*Rt+Rt);
x_FC1 = x_FC';
y_FC1 = y_FC';
% SECOND CURVE (SC)
% Angle for Second Curve
Angle_SC = -pi/2;
SC_step = ((theta_n-pi/2)-Angle_SC)/100;
theta_SC = -pi/2:SC_step:(theta_n-pi/2);
% Coordinates for Second Curve
x_SC = cos(theta_SC)*0.382*Rt;
y_SC = sin(theta_SC)*0.382*Rt+(0.382*Rt+Rt);
x_SC1 = x_SC';
y_SC1 = y_SC';
% THIRD CURVE (TC)
% Coordinates for Third Curve
x_TC = cos(theta_n-pi/2)*0.382*Rt;
y_TC = sin(theta_n-pi/2)*0.382*Rt+(0.382*Rt+Rt);
% Exit Coordinates
y_exit = sqrt(area_ratio)*Rt;
matrix_y = [y_TC^2 y_TC 1; y_exit^2 y_exit 1; 2*y_TC 1 0];
matrix_x = [x_TC; Ln ;1/tan(theta_n)];
x_exit = matrix_y^-1*matrix_x;
a = x_exit(1,1);
b = x_exit(2,1);
c = x_exit(3,1);
y = y_TC:0.8:y_exit;
x = a*y.^2+b*y+c;
% Complete Coordinate
Rao_x = [x_FC x_SC x];
Rao_y = [y_FC y_SC y];
% Lower Geometry
Rao_y1 = -1*Rao_y;
%Coordinates
R_X = Rao_x';
R_Y = Rao_y';
Rao = [R_X R_Y];
% Figures
figure(1)
plot (Rao_x,Rao_y,'r','LineWidth',3)
hold on
plot (Rao_x,Rao_y1,'r','LineWidth',3)
hold of
I need this code To be generate in 3D model
can you please provide

카테고리

도움말 센터File Exchange에서 Get Started with Curve Fitting Toolbox에 대해 자세히 알아보기

태그

아직 태그를 입력하지 않았습니다.

질문:

2011년 4월 14일

답변:

2023년 8월 27일

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by