필터 지우기
필터 지우기

vpasolve for three nonlinear equations inside a for loop

조회 수: 2 (최근 30일)
SACHIN VERMA
SACHIN VERMA 2020년 6월 14일
댓글: Ameer Hamza 2020년 6월 15일
I am trying to solve the system of the three non-linear equations by using vpasolve for different values of parameter U that varies from 0-0.5, while other parameters are fixed. My code is just showing output for U=0, then it's showing an error(Second argument must be a vector of symbolic variables).
clc
clear all;
syms x y w z eb
t = 0.2./pi;
d = 0.2./pi;
U = 0;
while (U<0.5)
e=U./2;
a = U./(pi.*t);
f = imag((U./d).*((((t./d)./(sqrt(1-z.^2)))+w)./((z.^2.*(1+2.*(t./d)./sqrt(1-z.^2)))-(2.*(t./d).*w./...
sqrt(1-z.^2))-(t./d).^2-(( -e + U.*x)./d).^2-w.^2)));
g = imag((z+(( -e + U.*x)./d)+((t./d).*z)./(sqrt(1-z.^2)))./((z.^2.*(1+2.*(t./d)./sqrt(1-z.^2)))-(2.*(t./d).*w./...
sqrt(1-z.^2))-(t./d).^2-(( -e + U.*x)./d).^2-w.^2));
h = imag((z+((-e + U.*y)./d)+((t./d).*z)./(sqrt(1-z.^2)))./((z.^2.*(1+2.*(t./d)./sqrt(1-z.^2)))-(2.*(t./d).*w./...
sqrt(1-z.^2))-(t./d).^2-((-e + U.*y)./d).^2-w.^2));
s=int(f,z,-Inf,0);
u=int(g,z,-Inf,0);
v=int(h,z,-Inf,0);
eq1=w-(-1./pi).*s==0;
eq2=y-(-1./pi).*u==0;
eq3=x-(-1./pi).*v==0;
% sol = vpasolve(eqs,vars);
[x,y,w] = vpasolve([eq1, eq2, eq3],[x,y,w],[1 0 0]);
%[sol.x sol.y sol.w]
%solutions = [solx,soly,solw]
n_up = double(x);
n_down = double(y);
d_ind = double(w);
m = abs(n_up-n_down);
eqn=((eb.*(1+2.*(t./d)./sqrt(1-eb)))-(2.*(t./d).*d_ind./sqrt(1-eb))-(t./d).^2-(( -e + U.*n_up)./d).^2-d_ind.^2);
e_abs = vpasolve(eqn,eb);
e_abs1=sqrt(e_abs);
e_abs2=-sqrt(e_abs);
weight = ((1./2).*(1-(e_abs1).^2).*(((sqrt(1-e_abs1.^2)).*(1+((( -e + U.*n_up)./d)./(e_abs1))))./(((1-(e_abs1).^2)...
.*((sqrt(1-e_abs1.^2))+2.*(t./d)))+((t./d).*e_abs1.^2)+(t./d).*(d_ind./d))));
fprintf('%8.4f %8.4f %8.4f %8.4f %8.4f %8.4f %8.4f %8.4f\n', [a,n_up,n_down,m,d_ind,e_abs1,e_abs2,weight]');
if (U==0.5)
break
end
U = U+0.1;
end
  댓글 수: 2
SACHIN VERMA
SACHIN VERMA 2020년 6월 14일
its showing following error....................
0.0000 0.2178 0.2178 0.0000 0.0000 0.5437 -0.5437 0.1288
Error using sym.getEqnsVars>checkVariables (line 92)
Second argument must be a vector of symbolic variables.
Error in sym.getEqnsVars (line 54)
checkVariables(vars);
Error in sym/vpasolve (line 132)
[eqns,vars] = sym.getEqnsVars(varargin{1:N});
Error in finite_scgap_main (line 27)
[x,y,w] = vpasolve([eq1, eq2, eq3],[x,y,w],[1 0 0]);

댓글을 달려면 로그인하십시오.

채택된 답변

Ameer Hamza
Ameer Hamza 2020년 6월 14일
In this line
[x,y,w] = vpasolve([eq1, eq2, eq3],[x,y,w],[1 0 0]);
you are overwriting the values of x, y, and w and converting them from symbolic to numeric. Use different variable names. See the following code
clc
clear all;
syms x y w z eb
t = 0.2./pi;
d = 0.2./pi;
U = 0;
while (U<0.5)
e=U./2;
a = U./(pi.*t);
f = imag((U./d).*((((t./d)./(sqrt(1-z.^2)))+w)./((z.^2.*(1+2.*(t./d)./sqrt(1-z.^2)))-(2.*(t./d).*w./...
sqrt(1-z.^2))-(t./d).^2-(( -e + U.*x)./d).^2-w.^2)));
g = imag((z+(( -e + U.*x)./d)+((t./d).*z)./(sqrt(1-z.^2)))./((z.^2.*(1+2.*(t./d)./sqrt(1-z.^2)))-(2.*(t./d).*w./...
sqrt(1-z.^2))-(t./d).^2-(( -e + U.*x)./d).^2-w.^2));
h = imag((z+((-e + U.*y)./d)+((t./d).*z)./(sqrt(1-z.^2)))./((z.^2.*(1+2.*(t./d)./sqrt(1-z.^2)))-(2.*(t./d).*w./...
sqrt(1-z.^2))-(t./d).^2-((-e + U.*y)./d).^2-w.^2));
s=int(f,z,-Inf,0);
u=int(g,z,-Inf,0);
v=int(h,z,-Inf,0);
eq1=w-(-1./pi).*s==0;
eq2=y-(-1./pi).*u==0;
eq3=x-(-1./pi).*v==0;
% sol = vpasolve(eqs,vars);
[xv,yv,wv] = vpasolve([eq1, eq2, eq3],[x,y,w],[1 0 0]);
%[sol.x sol.y sol.w]
%solutions = [solx,soly,solw]
n_up = double(xv);
n_down = double(yv);
d_ind = double(wv);
m = abs(n_up-n_down);
eqn=((eb.*(1+2.*(t./d)./sqrt(1-eb)))-(2.*(t./d).*d_ind./sqrt(1-eb))-(t./d).^2-(( -e + U.*n_up)./d).^2-d_ind.^2);
e_abs = vpasolve(eqn,eb);
e_abs1=sqrt(e_abs);
e_abs2=-sqrt(e_abs);
weight = ((1./2).*(1-(e_abs1).^2).*(((sqrt(1-e_abs1.^2)).*(1+((( -e + U.*n_up)./d)./(e_abs1))))./(((1-(e_abs1).^2)...
.*((sqrt(1-e_abs1.^2))+2.*(t./d)))+((t./d).*e_abs1.^2)+(t./d).*(d_ind./d))));
fprintf('%8.4f %8.4f %8.4f %8.4f %8.4f %8.4f %8.4f %8.4f\n', [a,n_up,n_down,m,d_ind,e_abs1,e_abs2,weight]');
if (U==0.5)
break
end
U = U+0.1;
end
  댓글 수: 2
SACHIN VERMA
SACHIN VERMA 2020년 6월 14일
편집: SACHIN VERMA 2020년 6월 14일
got it, thank you so much Ameer Sir...have a nice day
Ameer Hamza
Ameer Hamza 2020년 6월 15일
I am glad to be of help!

댓글을 달려면 로그인하십시오.

추가 답변 (0개)

카테고리

Help CenterFile Exchange에서 Loops and Conditional Statements에 대해 자세히 알아보기

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by