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Question regarding impoly restraint to move about a specified path

조회 수: 1 (최근 30일)
Lets say I have an implicit equation in x and y f(x,y)=x^2 + y^2 -5*x +12*y +24 which is an example. I construct an impoly with three or n number of vertices over the curve.My question is how can I restrict the movement of vertices of impoly to be restricted to follow the path of the curve.
  댓글 수: 2
darova
darova 2020년 6월 12일
PLease attach some example or something
Saikat Banerjee
Saikat Banerjee 2020년 6월 12일
I have already attached example. Read question carefully. Let us say we construct a circle through fimplicit(x^2 + y^2 -5*x +12*y +24). After that we construct a traingle with three vertices using impoly. Now the vertices of the triangle will only move along the Circle. Restrain the movement of vertices using impoly along the circle. It will not go inside the circle or can come out of the circle. It will only move on the curve of the Circle

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채택된 답변

darova
darova 2020년 6월 13일
Use setPositionConstraintFcn function
function main
clc,clear
x = 0:.05:10;
y = sin(x);
plot(x,y,'.-r')
h = impoly(gca,[0:2; sin(0:2)]'); % create impoly on the curve
setPositionConstraintFcn(h,@fcn) % assign constraint
function newPos = fcn(currPos)
d = pdist2([x(:) y(:)],currPos);
[~,ix] = min(d); % find closest points
newPos = [x(ix); y(ix)]'; % constrained position
end
end

추가 답변 (1개)

Ameer Hamza
Ameer Hamza 2020년 6월 12일
You can use fimplicit() to get the points on the equation and then pass those points to impoly()
f = @(x, y) x.^2 + y.^2 - 5*x + 12*y + 24;
fi = fimplicit(f, [-3 8 -15 0]);
x = fi.XData;
y = fi.YData;
  댓글 수: 2
Saikat Banerjee
Saikat Banerjee 2020년 6월 13일
I construct impoly as h=impoly([-1,-5];[3,-1];[5,-8]); Now give the rest of the code. I can't understand
Saikat Banerjee
Saikat Banerjee 2020년 6월 14일
This answer is also of help but the other one is better

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