help to input sqrt function

z=sqrt(sin(x.^2+y.^2))\sqrt(x.^2+y.^2)

is this code input correct for this function

z=(sin√(x^2+y^2 ))/√(x^2+y^2 )

Answer 1

[Walter Roberson]

z = sqrt(sin(x.^2+y.^2)) ./ sqrt(x.^2+y.^2);

[Walter Roberson]

z = sqrt(sinc(x.^2 + y.^2))

[marwan alamah]

it did not work

tell me it is undefined function or variable x

what should i do

[Walter Roberson]

It is not clear why you would want to compute z=sqrt(sin(x.^2+y.^2))\sqrt(x.^2+y.^2) if x and y are not defined?

Perhaps you are wanting to create a function. If so then Rohith Nomula's "myfun" would work.

Answer 2

[Rohith Nomula]

For this

z=(sin√(x^2+y^2 ))/√(x^2+y^2 )

For x and y as single elements

 z=sin(sqrt(1^2+2^2))
 z=z/(sqrt(1^2+2^2))

For a function

function z = myfuc(x,y)
    z= sin(sqrt(x^2+y^2))/sqrt(x^2+y^2);
end

Try declaring it this way

[Walter Roberson]

The code to be implemented involves the dot versions of the operators, so the function should as well:

function z = myfuc(x,y)
    z= sin(sqrt(x.^2+y.^2)) ./ sqrt(x.^2+y.^2);
end