inputing pi in syms
이전 댓글 표시
Hello,
I am working with the code bellow & R2020a.
The answer provided is:
result: 
which is correct.
However, I would much prefare the answer to be given in the form:
aim: 
Is there a way to do so?
So far I tried using
pi = sym('pi')
and
pi = sym(pi)
or just pi as a symbol.
In the best senario I get the number answer (389.6364); in the worst I obtain this:
Thank you,
The code used:
syms k x L E I
pi = sym(pi)
% Trial function
w = k * (1- cos(2*pi*x/L))
% Derivatives
w_x = diff(w,x,1)
w_xx = diff(w,x,2)
% x_y = diff(w,y,1)
% x_yy = diff(w,y,2)
% Strain
U = 1/2* int((E*I*w_xx^2),[0,L])
댓글 수: 5
madhan ravi
2020년 6월 7일
Why do you expect the sun part to disappear?
Aleksander Tyczynski
2020년 6월 7일
madhan ravi
2020년 6월 7일
Yes but once you define pi using syms it doesn’t revalues the expression.
Aleksander Tyczynski
2020년 6월 7일
편집: Aleksander Tyczynski
2020년 6월 7일
Surya Talluri
2020년 8월 10일
I have checked with R2020a and the code that you have mentioned is working fine for me with sin(4pi) turning to zero.

답변 (0개)
카테고리
도움말 센터 및 File Exchange에서 Conversion Between Symbolic and Numeric에 대해 자세히 알아보기
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!