Changing the bits randomly

I have a binary value

10000100000 which is 1056

i am changing last 5 bits

10000111111 which is 1087

now keeping last 5 bits constant i have to change other bits to get closer value of 1056

for ex i have changed one bit from 1 to 0

10000011111 which is 1055..like this i have to check,please tell how to process in a loop and check all bits ,manually i checked ,but i need in a for loop,or using GA

PLEASE HELP

Answer 1

[Jan]

x = 1087;
for bit = 6:16
  orig = bitget(x, bit);
  new  = bitset(x, bit, 1-orig);
  if new < x
    x = new;
  end
end

[kash]

Jan can u please tell which variable is the output

because in new variable i get value as 32799

and in x i get 31 in which two variables does not give the result which is close to 1056,plese provide assistance

Answer 2

[C.J. Harris]

Try this, it is a somewhat brute force approach to solving your problem. The value 'nMatch' should give you the desired answer:

nInput = 1056;

A = dec2bin(nInput);
A(end-4:end) = '1';

nRest   = 2^length(A(1:end-5)) - 1;
nCombs  = dec2bin(0:nRest);

maxErr = Inf;

for nCount = 1:nRest

      testVal = bin2dec([nCombs(nCount,:) A(end-4:end)]);

      if abs(nInput - testVal) < maxErr

          maxErr = abs(nInput - testVal);
          nMatch = testVal;

      end

end

Answer 3

[C.J. Harris]

or less brute force without a for loop:

nInput = 1056;

nShift  = bin2dec('11111');
nOffset = nInput - nShift;

nNear  = round(nOffset/(nShift + 1));
nMatch = nNear*(nShift + 1) + nShift;

[kash]

ok thanks harris ,but i want to perform for wav signals

I have to embed 2nd wave signal in 1st wave signal

the 2nd wave bit length is less than 1st,

please can u help

assuming the 1st wave signal length for ex

100010101010101000000

second is

11111001

i need to embed 2nd in 1st

100010101010111111001 ans then process it