No output in my problem

조회 수: 2 (최근 30일)
Mojtaba Mohareri
Mojtaba Mohareri 2020년 5월 18일
댓글: Mojtaba Mohareri 2020년 5월 18일
I was wondering if somebody could help me about the following code which doesn't have output as a figure. Thanks in advance.
clc
clear
n = 1000;
a = 0;
b = 7;
h = (b-a)/n;
x(1) = 0.009;
y(1) = 0.001;
z(1)=0.99;
t(1)=a;
f=@(t,x1,x2,x3) -0.002*x1+0.018*x2-0.10*x1+(1-0.10)*(0.01+(0.99/(1+exp(-2*t+8)))+1)*((x3*x2)/(x1+x2+x3))+0.06*(1-0.05)*x3
g=@(t,x1,x2,x3) -0.018*x2+0.002*x1-0.10*x2+0.05*0.06*x3+0.10*(0.01+0.99/(1+exp(-2*t+8))+1)*((x3*x2)/(x1+x2+x3))
c=@(t,x1,x2,x3) -(0.01+0.99/(1+exp(-2*t+8))+1)*((x3*x2)/(x1+x2+x3))-0.06*x3+0.10*x2+0.10*x1
for i=1:n-1
t(i+1) = a + i*h;
end
disp('Step t x y z');
disp('----------------------------------------------------');
fprintf('0 %2.2f %2.16f %2.16f %2.16f\n', t(1),x(1),y(1),z(1));
for k=1:n-1
f1 = f(t(k),x(k),y(k),z(k));
g1 = g(t(k),x(k),y(k),z(k));
c1 = c(t(k),x(k),y(k),z(k));
f2 = f(t(k)+(h/2), x(k)+(h/2)*f1 , y(k)+(h/2)*g1 ,z(k)+(h/2)*c1);
g2 = g(t(k)+(h/2), x(k)+(h/2)*f1 , y(k)+(h/2)*g1 ,z(k)+(h/2)*c1);
c2 = c(t(k)+(h/2), x(k)+(h/2)*f1 , y(k)+(h/2)*g1 ,z(k)+(h/2)*c1);
f3 = f(t(k)+(h/2), x(k)+(h/2)*f2 , y(k)+(h/2)*g2,z(k)+(h/2)*c2);
g3 = g(t(k)+(h/2), x(k)+(h/2)*f2 , y(k)+(h/2)*g2,z(k)+(h/2)*c2);
c3 = c(t(k)+(h/2), x(k)+(h/2)*f2 , y(k)+(h/2)*g2,z(k)+(h/2)*c2);
f4 = f(t(k)+h , x(k)+h*f3 , y(k)+h*g3,z(k)+h*c3);
g4 = g(t(k)+h , x(k)+h*f3 , y(k)+h*g3,z(k)+h*c3);
c4 = c(t(k)+h , x(k)+h*f3 , y(k)+h*g3,z(k)+h*c3);
x(k+1) = x(k) + (h/6)*(f1 + 2*f2 + 2*f3 + f4);
y(k+1) = y(k) + (h/6)*(g1+ 2*g2 + 2*g3 + g4);
z(k+1) = z(k) + (h/6)*(c1+ 2*c2 + 2*c3 + c4);
fprintf('%2f %2.2f %2.16f %2.16f %2.16f\n', k, t(k+1),x(k+1),y(k+1), z(k+1));
end
n = 1000;
a = 0;
b = 7;
h = (b-a)/n;
p(1) = 0;
q(1) = 0;
r(1) = 0;
t(1) = b;
f=@(t,x1,x2,x3) 0.018*(x1-x2)+0.10*(x1-x3)+((x3-0.10*x1-(1-0.10)*x2)*(0.01+(0.99)/(1+exp(-2*t+8))+1)*z(k)*(x(k)+z(k)))/((x(k)+y(k)+z(k))^2)
g=@(t,x1,x2,x3) 0.002*(x2-x1)+0.10*(x2-x3)-((x3-0.10*x1-(1-0.10)*x2)*(0.01+(0.99)/(1+exp(-2*t+8))+1)*z(k)*y(k))/((x(k)+y(k)+z(k))^2)
c=@(t,x1,x2,x3) -1+(x3-0.05*x1-(1-0.05)*x2)*0.06+((x3-0.10*x1-(1-0.10)*x2)*(0.01+(0.99)/(1+exp(-2*t+8))+1)*y(k)*(x(k)+y(k)))/((x(k)+y(k)+z(k))^2)
for i=1:n-1
t(i+1) = b - i*h;
end
disp('Step t x y z');
disp('----------------------------------------------------');
fprintf('0 %2.2f %2.16f %2.16f %2.16f\n', t(1),p(1),q(1),r(1));
for k=1:n-1
f1 = f(t(k),p(k),q(k),r(k));
g1 = g(t(k),p(k),q(k),r(k));
c1 = c(t(k),p(k),q(k),r(k));
f2 = f(t(k)-(h/2), p(k)-(h/2)*f1 , q(k)-(h/2)*g1 ,r(k)-(h/2)*c1);
g2 = g(t(k)-(h/2), p(k)-(h/2)*f1 , q(k)-(h/2)*g1 ,r(k)-(h/2)*c1);
c2 = c(t(k)-(h/2), p(k)-(h/2)*f1 , q(k)-(h/2)*g1 ,r(k)-(h/2)*c1);
f3 = f(t(k)-(h/2), p(k)-(h/2)*f2 , q(k)-(h/2)*g2, r(k)-(h/2)*c2);
g3 = g(t(k)-(h/2), p(k)-(h/2)*f2 , q(k)-(h/2)*g2, r(k)-(h/2)*c2);
c3 = c(t(k)-(h/2), p(k)-(h/2)*f2 , q(k)-(h/2)*g2, r(k)-(h/2)*c2);
f4 = f(t(k)-h , p(k)-h*f3 , q(k)-h*g3,r(k)-h*c3);
g4 = g(t(k)-h , p(k)-h*f3 , q(k)-h*g3,r(k)-h*c3);
c4 = c(t(k)-h , p(k)-h*f3 , q(k)-h*g3,r(k)-h*c3);
p(k+1) = p(k) - (h/6)*(f1 + 2*f2 + 2*f3 + f4);
q(k+1) = q(k) - (h/6)*(g1+ 2*g2 + 2*g3 + g4);
r(k+1) = r(k) - (h/6)*(c1+ 2*c2 + 2*c3 + c4);
fprintf('%2f %2.2f %2.16f %2.16f %2.16f\n', k, t(k+1),p(k+1),q(k+1), r(k+1));
end
figure
plot(t,min(max(0,((r-(1/10)*p-(1-(1/10))*q).*z.*y)/(2*(1/100)*(x+y+z))),1))
axis([0 7 0 1]);
xlabel('time')
ylabel('Control U2')

채택된 답변

Walter Roberson
Walter Roberson 2020년 5월 18일
plot(t,min(max(0,((r-(1/10)*p-(1-(1/10))*q).*z.*y)./(2*(1/100)*(x+y+z))),1))
That is, your / has to be ./
  댓글 수: 1
Mojtaba Mohareri
Mojtaba Mohareri 2020년 5월 18일
Thank you very much

댓글을 달려면 로그인하십시오.

추가 답변 (0개)

카테고리

Help CenterFile Exchange에서 Graphics Object Programming에 대해 자세히 알아보기

태그

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by