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how to identify leap years

조회 수: 35 (최근 30일)
Anisia a
Anisia a 2020년 5월 18일
답변: Siva Charan 2023년 9월 30일
Hi,
I am trying to create a function that takes 3 +ve integer scalar inputs year, month and date. If these 3 represent a valid date return true otherwise return false. My code is running for most of the input. But I am having problem with leap years. The code I wrote is given below. Can anyone please point out my mistake.
function valid= valid_date(year, month, date)
v=1;
a= mode(year,4);
b= mode(year,100);
c= mode(year,400);
if ~isscalar(year) || year<1 || year~=fix(year) || ~isscalar(month) || month<1 || month~=fix(month) ||~isscalar(date)|| date<1 || date~=fix(date)
v= 0;
end
if v==0
valid=false;
return
end
if 0>month || month>12
v= 0;
elseif (month==1 ||month==3|| month==5 || month==7 || month==8|| month==10|| month==12)
if 0<date&& date<=31
v=1;
else
v=0;
end
elseif (month== 4 ||month==6|| month==9 || month==11)
if 0<date&& date<31
v=1;
else
v=0;
end
elseif month==2
if date==29
if (a==0 && b~=0) || c==0
v=1;
else
v=0;
end
elseif 0<date && date<29
v=1;
else
v=0;
end
end
if v==0
valid=false;
else
valid=true;
end

답변 (2개)

Siva Charan
Siva Charan 2023년 9월 30일
Use this subfunction and call from the main function.
if the year is divisible by 100 and not divisible by 400, it is not a leap year. millennium years(1600, 1700, 1800...) should be divisible by 400 to be leap years, for others, any year that is divisible by 4 can be a leap year.
function leapyear = checkleap(year)
if mod(year,100)==0
if mod(year,400)==0
leapyear = true;
else
leapyear = false;
end
elseif mod(year,4) == 0
leapyear = true;
else
leapyear = false;
end
end

Stijn Haenen
Stijn Haenen 2020년 5월 18일
편집: Stijn Haenen 2020년 5월 18일
There is a leap year every four years, so you can use this:
if mod(year,4)==0
'leap year'
else
'not a leap year'
end
  댓글 수: 4
Stephen23
Stephen23 2020년 5월 18일
These are all divisible by four: 1500, 1700, 1800, 1900, 2100, 2200, 2300, 2500, but none of them are leap years.
Steven Lord
Steven Lord 2020년 5월 18일
Yes. The Wikipedia page has the algorithm for how to determine whether a year is a leap year.

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