Grouping sequence within interval

조회 수: 3 (최근 30일)
Benu
Benu 2020년 5월 17일
댓글: Benu 2020년 6월 5일
I got stuck in grouping my sequence.
How can I automatically grouping element of sequence? within interval for this case maybe 0.5
suppose I have 3 sequence
V1 = [0.73 0.74 0.77 0.78 0.79 11.17 11.18 11.19 11.20 11.22 11.23];
V2 = [0.71 0.78 0.76 6.04 6.08 6.01 11.38 11.4 11.1] ;
V3 = [0.73 0.74 0.75 4.29 4.33 7.83 7.85 11.38 11.34]
My expectation is to have a group as follows
G1 = {[0.73 0.74 0.77 0.78 0.79] ; [11.17 11.18 11.19 11.20 11.22 11.23]}
G2 = {[0.71 0.78 0.76] ; [6.04 6.08 6.01] ; [11.38 11.4 11.1] }
G3 = {[0.73 0.74 0.75] ; [4.29 4.33] ; [7.83 7.85] ; [11.38 11.34]}

채택된 답변

Thiago Henrique Gomes Lobato
Thiago Henrique Gomes Lobato 2020년 5월 17일
Something like this should do the trick for you
V1 = [0.73 0.74 0.77 0.78 0.79 11.17 11.18 11.19 11.20 11.22 11.23];
V2 = [0.71 0.78 0.76 6.04 6.08 6.01 11.38 11.4 11.1] ;
V3 = [0.73 0.74 0.75 4.29 4.33 7.83 7.85 11.38 11.34]
Vsorted = sort(V3); % Works also with V1, V2
NewSeqLocations = find(diff(Vsorted)>0.5); % 0.5 is your interval, i.e, maximum difference between adjacent numbers
NewSeqLocations = [0,NewSeqLocations,length(Vsorted)]; % Last sequence ends at last array element and starts at first element
Seq = cell(length(NewSeqLocations)-1,1); % Save sequences in cell array
for idx=1:length(Seq)
Seq{idx} = Vsorted(NewSeqLocations(idx)+1:NewSeqLocations(idx+1));
end
Seq{:}
ans =
0.730000000000000 0.740000000000000 0.750000000000000
ans =
4.290000000000000 4.330000000000000
ans =
7.830000000000000 7.850000000000000
ans =
11.340000000000000 11.380000000000001
  댓글 수: 1
Benu
Benu 2020년 6월 5일
I never think this kind of a way. this is really help me.
wonderful ! Thank you so much !

댓글을 달려면 로그인하십시오.

추가 답변 (0개)

카테고리

Help CenterFile Exchange에서 Matrix Indexing에 대해 자세히 알아보기

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by