how to write if statement for matrix ?

how to write if statement for matrix ?

in other words:

test= [5;6;0;-1;0]

this is the condition:

if test==0
    disp 0
    
else
    disp 5
    
end

and I want to give answer for each row (for 5 and 6 and 0 ....etc)

Answer 1

[Geoff Hayes]

Ibrahim - what are you trying to do here? Just display (with disp) a message depending upon whether an element is a zero or not? The simplest and least efficient way to do this is with a loop

test = [5;6;0;-1;0];
for k = length(test)
    if test(k) == 0
        disp 0;
    else
        disp 5;
    end
end

I don't think that is what you really want though so you may need to provide more details. I also suspect that you shouldn't need to use a for loop and that may be the case depending upon the details you provide.

[Ibrahim AlZoubi]

I have two matrices first one is:

test = [5;6;0;-1;0;5;0;6;0;8];

and the second one is:

test5 = [2;6;8;-1;0;7;8;6;8;8];

how to generate third matrix which is the result after the condition (if statment)...

the condition is if the value of test is equal 0 then the value of the new matrix is 0 , else if the value of the first matrix isn't equal 0 do some calculations on the second matrix which is test5 like (test5*7+5).

so the third matrix values depends on the two matrix before...

[Geoff Hayes]

Is the output array of the same dimensions as test?

test = [5;6;0;-1;0];
outputArray = size(test);
for k = length(test)
    if test(k) == 0
        outputArray(k) = 0;
    else
        % do a calculation of some kind
        outputArray(k) = 42; % <--- your code here
    end
end