Index exceeds the number of array elements (6).

조회 수: 3 (최근 30일)
Sinan Yigit
Sinan Yigit 2020년 5월 14일
답변: Ayush Goyal 2020년 6월 19일
I get this error and do not solve the problem please inform me how to solve it.
related codes,
for i=1:6
tt(1)=0;
yol=sqrt((xr(i+1)-xr(i))^2+(yr(i+1)-yr(i))^2);
tt(i+1)=tt(i)+yol/Vr;
end
xrr=horzcat(tt',xr);
yrr=horzcat(tt',yr);
xr - yr values;
3 - 3
2.68060147430381 - 3.13671296448901
4.36591862294010- 6.36978774648130
6.81142757321166- 7.19528445914528
7.75732360564317- 4.90764974391571
8- 5
thanks for helps.
  댓글 수: 1
Sriram Tadavarty
Sriram Tadavarty 2020년 5월 14일
Hi Sinan,
At the loop 6, the code access xr(6+1) which is not present. Inorder to solve this, you can append zeros at the front of xr and yr. The other one, being looping from 1:5. The actual case depends on what you needed in the output.
Hope this helps.
Regards,
Sriram

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답변 (1개)

Ayush Goyal
Ayush Goyal 2020년 6월 19일
From my understanding of the question you are facing index issue in your code. Since you are iterating your for loop from i=1 to i=6, so when i=6 the code is accessing xr(6+1) and yr(6+1) but the length of both xr and vr vector is 6. You should iterate your for loop for i=1:5 or you can append zeros at the end of xr and yr. You can refer to the following link for how to append to array or vector:

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