Better way to use circshift
이전 댓글 표시
I am trying to create array B from array A (of course in the real application the numbers are not sequential and the arrays are much biggger i.e. 5000x5000)
B =
5 0 1 2 3 4
4 5 0 1 2 3
3 4 5 0 1 2
2 3 4 5 0 1
1 2 3 4 5 0
A =
0 1 2 3 4 5
0 1 2 3 4 5
0 1 2 3 4 5
0 1 2 3 4 5
0 1 2 3 4 5
Here is my solution:
for i = 1:5 B(i,:) = circshift(A(i,:),[0,i]); end
Is there a better (i.e. faster) way to do this? On a more general note, I get the fealing that using a for loop to act on a array is always a bad idea.
댓글 수: 2
Image Analyst
2012년 11월 1일
Wrong. Using for loops is not always a bad idea.
Brent
2012년 11월 2일
답변 (2개)
If the matrix is going to be sparse, this should be pretty fast
B=interpMatrix([5 4 3 2 1],1,6,1,'circ');
B(end,:)=[];
Sean de Wolski
2012년 11월 1일
v = 0:5;
B = gallery('circul',v);
B = B(2:end,:);
A = repmat(v,[numel(v)-1,1]);
댓글 수: 3
Matt J
2012년 11월 1일
Careful. GALLERY has had a hard time producing large sparse circulant matrices, as discussed here
Don't know if they fixed this in more recent MATLAB versions...
Sean de Wolski
2012년 11월 1일
tic,B = gallery('circul',1:5000);toc
Elapsed time is 0.603616 seconds.
Matt J
2012년 11월 1일
It seems to be doing better in terms of memory management, compared to past MATLAB versions, but it's still slow. Take the example from my link. In R2012a, I get these timings:
r=[1 2 3 4 sparse(zeros(1,10000))];
tic; A=gallery('circul',r); toc
Elapsed time is 4.887724 seconds.
tic; A=interpMatrix(r,1,length(r),1,'circ').'; toc
Elapsed time is 0.005704 seconds.
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