loop and array for sum

magnitude= abs(y); % amplitude of y signal

near= ceil(N/F);

signal= zeros(1,near);

for i=1:1000:N

for j=i:1:near

s = sum(magnitude(i:i+1000));

signal(j)= s;

end

end

I am trying to store every sum in array but instead, i get same result for every signal(j). I think i am missing something.

Answer 1

[Steven Lord]

The expression you use to calculate s doesn't depend on j and also doesn't depend on anything that changes inside the loop over j. So it's expected that you receive the same answer each time.

I don't know how you want to modify your code so that the expression you use to calculate s has some dependence on j. If you post the mathematical expression you're trying to compute or the problem you're trying to solve as a comment we may be able to offer some guidance.

[Irem Kuzgunkaya]

i have a 232 second long signal with N=1000. I want to sum magnitude of every 1000 sample and put every sum in the signal array.

Answer 2

[drummer]

s = s + sum(magnitude(i:i+1000));

would it work?

[Irem Kuzgunkaya]

i tried it but it doesn't.