Hi
I would like to plot a 3D ellipsoid without matlab's functions and thanks to an implicit equation
Best regard

댓글 수: 2

James Tursa
James Tursa 2020년 5월 9일
"... without matlab's functions ..."
What does this mean? As written, this is impossible.
Marsu567
Marsu567 2020년 5월 9일
Sans utiliser une fonction ou fontionnalité préprogrammée dans matlab tel ellipsoid() ou fimplicit() ou autres
Merci

댓글을 달려면 로그인하십시오.

답변 (1개)

Ameer Hamza
Ameer Hamza 2020년 5월 9일

0 개 추천

Try this
a = 1;
b = 0.5;
c = 2;
f = @(x,y,z) (x/a).^2 + (y/b).^2 + (z/c).^2 - 1;
fimplicit3(f, [-3 3 -3 3 -3 3]);
axis equal

댓글 수: 3

Marsu567
Marsu567 2020년 5월 9일
Merci
x = -1:1/100:1;
z = -1: 2/100 :1;
N = length(x);
N1 = length(z);
Zc = zeros(N1,N);
Xc = zeros(N1,N);
for i = 1:N
for j = 1:N1
[Xc, Yc] =meshgrid(x,z);
Zc(j,i) =sqrt(1-(Xc(j,i).^2)/2-(Yc(j,i).^2)/2)/2;
end
end
Xc = 0.05*Xc;
Yc = Yc;
Zc = 0.05*Zc;
surf(Xc, Yc, Zc)
Euclides
Euclides 2023년 7월 14일
편집: Euclides 2023년 7월 14일
quick question....... is it possible to replicate this sort of plot by using only the ellipsoidal radius (i.e, a function of theta, phi, a, b, and c)? For instance, for the ellipse, I can use the elliptical radius in polar coordinates (function of phi, a and b) and then use the in-built polarplot function to visualize ellipses of various shapes. I am looking for something equivalent for the ellipsoid case, but haven't found it so far. There is the in-built ellipsoid function, but that uses Cartesian coordinates and I want to directly use the ellipsoidal radius function. Any help is very welcome!

댓글을 달려면 로그인하십시오.

카테고리

도움말 센터File Exchange에서 Polar Plots에 대해 자세히 알아보기

태그

질문:

2020년 5월 9일

편집:

2023년 7월 14일

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by