Are you able to count the number of pixels in a 3D plot?

조회 수: 3 (최근 30일)
sui zhi lau
sui zhi lau 2020년 5월 5일
댓글: sui zhi lau 2020년 5월 7일
I am trying to find a way to count the number of red pixels in my moving plot and I was only able to find the number of white pixels in only at an angle. Would it be possible to count the total number of red pixels in a 3D plot?
clc; % Clear the command window.
close all; % Close all figures (except those of imtool.)
clear; % Erase all existing variables. Or clearvars if you want.
workspace; % Make sure the workspace panel is showing.
xlabel('My x label') % Axis Labels
ylabel('My y label')
zlabel('My z label')
view([-37.5 30]) % standard 3D View
scale = 0.5;
y = 1; % white percentage
%% range of results
d = 10; % Distance Between each point
nmesh = 3; % range
MagR = 0; % Magnetic Radius (MagR>nmesh = Strong, MagR<nmesh = weak, MagR = 0 = no Mag)
niter = 200; % no. of jumps
[X,Y,Z] = meshgrid((-nmesh+1):nmesh-1); % create mesh
X = X * d;
Y = Y * d;
Z = Z * d;
%% random direction for X,Y,Z directions
dx = normrnd(0,1,[(size(X,1))^3 niter]);
dy = normrnd(0,1,[(size(X,1))^3 niter]);
dz = normrnd(0,1,[(size(X,1))^3 niter]);
%% Magnetised particles
c0 = nmesh; % center of magnetic field
for i = 1:size(dx,1)
[ii,jj,kk] = ind2sub(size(X),i); % row and column of force
n = pdist2([ii jj kk],[c0 c0 c0]); % distance to point
if n < MagR % radius of magnetic force
dx(i,:) = -cumsum(dx(i,:)*0+(jj-c0)/n); % cosinus
dy(i,:) = -cumsum(dy(i,:)*0+(ii-c0)/n); % sinus
dz(i,:) = -cumsum(dz(i,:)*0+(kk-c0)/n);
end
end
cla
hold on
%% For Loop to plot
for i = 1:niter-1
X1 = X(:) + dx(:,i);
Y1 = Y(:) + dy(:,i);
Z1 = Z(:) + dz(:,i);
plot3([X(:) X(:)]'+[dx(:,i+1) dx(:,i)]', ...
[Y(:) Y(:)]'+[dy(:,i+1) dy(:,i)]',...
[Z(:) Z(:)]'+[dz(:,i+1) dz(:,i)]','.-r','MarkerSize',5,'LineWidth',1)
%p.MarkerSize = 10; % 6 is the default
%p.LineWidth = 1; % 0.5 is the default
pause(0.01)
%% percentage readings
Image = getframe();
K = sum(sum(rgb2gray(Image.cdata)==255));
percentageofwhite(y) = K/numel(rgb2gray(Image.cdata))*100;
delete(findall(gcf,'type','text'))
txt=text(0.0,0.95,sprintf('White Space = %0.3f%%',percentageofwhite(y)),'Units','normalized');
y=y+1;
%%
xlim([-2*d 2*d]) % Axis limitsg
ylim([-2*d 2*d])
zlim([-2*d 2*d])
end
hold off
rotate3d on
  댓글 수: 5
Mrutyunjaya Hiremath
Mrutyunjaya Hiremath 2020년 5월 5일
plot3([X(:) X(:)]'+[dx(:,i+1) dx(:,i)]', ...
[Y(:) Y(:)]'+[dy(:,i+1) dy(:,i)]',...
[Z(:) Z(:)]'+[dz(:,i+1) dz(:,i)]','.-r','MarkerSize',5,'LineWidth',1)
According to this, you are drawing 125 pair red points in each iteration
sui zhi lau
sui zhi lau 2020년 5월 5일
hi Mrutyunjaya,
thank you for the fast repliy! how did you get that value and how would i be able to compared the red pixels compared to the total white percentage to get a percentage of it then?
Ash

댓글을 달려면 로그인하십시오.

답변 (2개)

darova
darova 2020년 5월 5일
Can you calculate the volume manually?
dv = [dx(:,i+1)-dx(:,i) dy(:,i+1)-dy(:,i) dz(:,i+1)-dz(:,i)];
V = V + pi*R*sqrt(sum(dv.^2,2)); % volume of all lines
  댓글 수: 9
sui zhi lau
sui zhi lau 2020년 5월 6일
Yes but what do i replace R with? For example i put my linewidth as 0.5, do i take my R as 0.5 ?

댓글을 달려면 로그인하십시오.


Mrutyunjaya Hiremath
Mrutyunjaya Hiremath 2020년 5월 6일
@ sui zhi lau,
Outside Loop
totalData = 0;
whitePixData = 40*40*40;
Inside Loop
redPixData(y) = sum(sqrt(((dx(:,i+1) - dx(:,i)).^2) + ((dy(:,i+1) - dy(:,i)).^2) + ((dz(:,i+1) - dz(:,i)).^2)));
totalData = totalData + redPixData(y);
percentageofred(y) = (totalData/whitePixData)*100;
txt=text(0.0,0.95,sprintf('White Space = %0.3f%%',percentageofred(y)),'Units','normalized');
  댓글 수: 3
Mrutyunjaya Hiremath
Mrutyunjaya Hiremath 2020년 5월 7일
because, we are not considering the elimination of overlapping area.
sui zhi lau
sui zhi lau 2020년 5월 7일
How would you consider with elimination of overlapping areas?

댓글을 달려면 로그인하십시오.

카테고리

Help CenterFile Exchange에서 3-D Volumetric Image Processing에 대해 자세히 알아보기

제품

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by