I have this program to get the value of "m"
clc
syms m
eqns = (72*m^2)-(1.5*m^3) == 358;
S=solve (eqns,m,'Real',true)
double (S.m);
However in the output I get this error
S =
32*cos(atan(2167511^(1/2)/5965)/3) + 16
16*3^(1/2)*sin(atan(2167511^(1/2)/5965)/3) - 16*cos(atan(2167511^(1/2)/5965)/3) + 16
16 - 16*3^(1/2)*sin(atan(2167511^(1/2)/5965)/3) - 16*cos(atan(2167511^(1/2)/5965)/3)
Error using sym/subsref
Too many output arguments.
Error in Untitled (line 5)
double (S.m);
Can any body help me with this?

 채택된 답변

Walter Roberson
Walter Roberson 2020년 5월 4일

1 개 추천

When there is only a single variable being solved for, and ReturnConditions is not set, then solve() does not return a structure containing the one variable: it returns the value of the variable. In terms of your code, that means you would use
double(S) %instead of double(S.m)
Or you could instead
S=solve (eqns, m, 'Real', true, 'returnconditions', true);
and then S.m would exist.

댓글 수: 3

Rohit Tamrakar
Rohit Tamrakar 2020년 5월 4일
Thanks Walter this worked.
I got this as answer.
ans =
47.8960
2.2849
-2.1809
I want the the value of "m" to be selected as 2.28 i.e the smallest positive integer among these three values. What code I have to use for selecting 2.28 value?
min(S(S>0))
Rohit Tamrakar
Rohit Tamrakar 2020년 5월 4일
Thanks Walter :)

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추가 답변 (1개)

Mathias Andersen
Mathias Andersen 2020년 5월 4일

1 개 추천

Double(S) will produce a matrix with the solutions.
S.m is not a variable stated anywhere in the script

댓글 수: 4

Rohit Tamrakar
Rohit Tamrakar 2020년 5월 4일
How can I get the value for variable "m" ?
Walter Roberson
Walter Roberson 2020년 5월 4일
S is the output of solve(). If two or more variables were being solved for and a single output were given, then S would be a structure with one field for each variable being solved for, and then S.m would exist.
S.m would also be created if 'returnconditions', true is specified.
Mathias Andersen
Mathias Andersen 2020년 5월 4일
편집: Mathias Andersen 2020년 5월 4일
S contains the values for m
Walter Roberson
Walter Roberson 2020년 5월 4일
Not when you solve for a single variable and you do not have ReturnConditions true: in that case, MATLAB cannot tell that apart from the case where you want the non-struct version of the solution.

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