how do i delete questions?

I do not want to use assignin,evalin or eval. If you run the code you'll see that at the bottom the matrices for M_A, M_B, M_C and M_D are displayed. Please can you show me how I can have these variables as outputs and their matrices in the workspace? So far only the first output value (M_A)is showing up as an output, as "ans". I'd like it to say M_A, and same for the others (M_B, M_C and M_D). Please help

function [M_A, M_B, M_C, M_D] = DiagDom
A =  [ 1 4 0 1 1; -1 -5 9 -20 2 ; 15 1 4 5 1 ; 2 2 -5 0 0; 0 2 -3 1 -9];
B= [ 9 3 3; 12 3 2; 1 3 5];
C= [ 1 13 2; 1 3 9; -12 2 -1];
D= [ 5 -2 4 2; 0 3 -1 -1; 3 3 9 -5;1 1 1 5];
oldA =  [ 1 4 0 1 1; -1 -5 9 -20 2 ; 15 1 4 5 1 ; 2 2 -5 0 0; 0 2 -3 1 -9];
oldB= [ 9 3 3; 12 3 2; 1 3 5];
oldC= [ 1 13 2; 1 3 9; -12 2 -1];
oldD= [ 5 -2 4 2; 0 3 -1 -1; 3 3 9 -5;1 1 1 5];
M = {A,B,C,D}; 
for i=1:numel(M)
    count = 0;
    while(1) % Perform infinite loop, till you find the diagonally dominant matrix
        if itisDiagDom (M{i}) % If this is diagonally dominant, disp and break the loop
            disp (['Matrix M is diagonally-dominant']);
            celldisp(M) ; 
            disp([count]);
             
            break;
        else
            M{i} = M{i}(randperm(size(M{i}, 1)), :);
            count= count+1 ;
             disp([count]); 
         if count > 500
           if itisDiagDom (M{1})
               M_A = M{1}
           else 
               M_A = oldA
           end
           if itisDiagDom (M{2})
               M_B= M{2}
           else
               M_B= oldB
           end
           if itisDiagDom (M{3})
               M_C= M{3}
           else
               M_C= oldC
           end
           if itisDiagDom (M{4})
               M_D= M{4}
           else
               M_D= oldD
           end
           
           
          break ; 
         end
             % Randomly swaps rows
        end
    end
    
end
end 
function [isdom] = itisDiagDom( A ) 
isdom = true;
for r = 1:size(A,1)
    rowdom = 2 * abs(A(r,r)) > sum(abs(A(r,:)));
    isdom = isdom && rowdom;
end
if isdom == 0
    
   
    disp (['Matrix']);
    disp([A]);
    disp([' is not diagonally-dominant']);
    
elseif isdom == 1
        disp (['Matrix is diagonally-dominant']);
         disp([A]);
       
  
end
end

[Stephen23]

Original question by alroyp10, retrieved from Google Cache:

My function only stores the first output in the workspace :(

I do not want to use assignin,evalin or eval. If you run the code you'll see that at the bottom the matrices for M_A, M_B, M_C and M_D are displayed. Please can you show me how I can have these variables as outputs and their matrices in the workspace? So far only the first output value (M_A)is showing up as an output, as "ans". I'd like it to say M_A, and same for the others (M_B, M_C and M_D). Please help

function [M_A, M_B, M_C, M_D] = DiagDom
A =  [ 1 4 0 1 1; -1 -5 9 -20 2 ; 15 1 4 5 1 ; 2 2 -5 0 0; 0 2 -3 1 -9];
B= [ 9 3 3; 12 3 2; 1 3 5];
C= [ 1 13 2; 1 3 9; -12 2 -1];
D= [ 5 -2 4 2; 0 3 -1 -1; 3 3 9 -5;1 1 1 5];
oldA =  [ 1 4 0 1 1; -1 -5 9 -20 2 ; 15 1 4 5 1 ; 2 2 -5 0 0; 0 2 -3 1 -9];
oldB= [ 9 3 3; 12 3 2; 1 3 5];
oldC= [ 1 13 2; 1 3 9; -12 2 -1];
oldD= [ 5 -2 4 2; 0 3 -1 -1; 3 3 9 -5;1 1 1 5];
M = {A,B,C,D}; 
for i=1:numel(M)
    count = 0;
    while(1) % Perform infinite loop, till you find the diagonally dominant matrix
        if itisDiagDom (M{i}) % If this is diagonally dominant, disp and break the loop
            disp (['Matrix M is diagonally-dominant']);
            celldisp(M) ; 
            disp([count]);
             
            break;
        else
            M{i} = M{i}(randperm(size(M{i}, 1)), :);
            count= count+1 ;
             disp([count]); 
         if count > 500
           if itisDiagDom (M{1})
               M_A = M{1}
           else 
               M_A = oldA
           end
           if itisDiagDom (M{2})
               M_B= M{2}
           else
               M_B= oldB
           end
           if itisDiagDom (M{3})
               M_C= M{3}
           else
               M_C= oldC
           end
           if itisDiagDom (M{4})
               M_D= M{4}
           else
               M_D= oldD
           end
           
           
          break ; 
         end
             % Randomly swaps rows
        end
    end
    
end
end 
function [isdom] = itisDiagDom( A ) 
isdom = true;
for r = 1:size(A,1)
    rowdom = 2 * abs(A(r,r)) > sum(abs(A(r,:)));
    isdom = isdom && rowdom;
end
if isdom == 0
    
   
    disp (['Matrix']);
    disp([A]);
    disp([' is not diagonally-dominant']);
    
elseif isdom == 1
        disp (['Matrix is diagonally-dominant']);
         disp([A]);
       
  
end
end

[alexp10]

Bro...relax. People make mistakes. What do you gain from getting mad?

[Rik]

"I'd like to delete this thread. Stephen Cobeldick is purposely posting my question because he's frustrated that I don't understand functions. I made a silly mistake, I'd like to delete the thread please."

Although I could be wrong, I doubt he is frustrated because you don't understand functions. I suspect he is frustrated you removed your question, which removes a lot of the usefulnes of his answer. (I also don't really see an indication of him being mad) If you come across a post in you search for the answer to some question, would you read the answer to a question that states 'wefwef'?

Silly mistakes are fine. Everybody makes them. What is not fine is attempting to delete your question after you have received help. If you don't want people to know you silly mistakes, you shouldn't post anything to the internet at all. At some point you will make a silly mistake.

[alexp10]

No, he deleted his comment after his answer where he was frustrated (because I was a beginner in matlab). He was frustrated before, that's why I wanted to delete the question. I appreciated his first answer. Not his second one. But he deleted that.

[Rena Berman]

(Answers Dev) Restored edit

Answer 1

[Stephen23]

You need to call the function with all of its output arguments, e.g. (pick the names to suit your needs):

[A,B,C,D] = DiagDom();

Very basic MATLAB concepts, e.g. how to call functions with multiple output arguments, are explained in the introductory tutorials:

https://www.mathworks.com/help/matlab/getting-started-with-matlab.html

[alexp10]

[A,B,C,D] = DiagDom(

Hi, yes I can't seem to get my head around this. I don't want A,B,C,D to be my outputs, they are the inputs. They get checked if theyre diagonally dominant by swapping rows. The outputs are the diagonally dominant matrices, if they can't be made diagonally dominant then they're stored as the original matrix.

[Tommy]

At the location from which you are calling your function, MATLAB has no idea that A, B, C, D, M_A, M_B, M_C, and M_D exist within your function. It only knows that four variables are output by your function, and this line:

[A, B, C, D] = DiagDom();

assigns those four variables to A, B, C, and D, which are entirely different from the A, B, C, and D inside your function. If you'd like to store the four outputs in variables with different names, it is easy to do so:

[M_A, M_B, M_C, M_D] = DiagDom();

or maybe

[out1, out2, out3, out4] = DiagDom();

[alexp10]

Thankyou Tommy! Turns out that I had to write that line outside the function. Thanks alot!

[Tommy]

"Reason: Another answer is better"

alroyp10, only one answer was posted in response to the question, and it did sufficiently answer what was asked.

"how do i delete questions?"

See the third paragraph here:

https://www.mathworks.com/matlabcentral/answers/337723-how-to-remove-a-question-here#comment_449533

The first paragraph here:

https://www.mathworks.com/matlabcentral/answers/114179-how-can-i-eliminate-a-question-posted-on-this-forum#answer_122632

And many of the responses here:

https://www.mathworks.com/matlabcentral/answers/23929-deleted-questions