decimal to binary and grouping into another matrix

i have to convert a decimal value to binary and group every two digits to

form a new one dimensional matrix whose size is 1,4*rows*cols

 i tried this its not working ie

secret = [22 33

         22 44]

[rows,cols]=size(secret);

for i= 1 : rows

    for j= 1: cols

        binarysecret{i,j}=dec2bin(secret(i,j),8);

    end

end cc=1;

[r,c]=size(binarysecret)

for q = 1 : r

    for q1 = 1 : c

         while(x<8)

               y=x+1;

            secretDNA{cc} =  binarysecret{q,q1}(x:y)  

         x=x+2;

        cc=cc+1;

       end

    end

end

Thanks in advance

Answer 1

[Andrei Bobrov]

bi = dec2bin(secret,8) - '0';
out = reshape(mat2cell(bi,ones(size(bi,1),1),2*ones(size(bi,2)/2,1))',1,[]);

or

n = 8;
s = size(secret);
bi = rem(floor(reshape(secret',[],1)*pow2(1-n:0)),2);
out = reshape(mat2cell(bi,ones(prod(s),1),2*ones(n/2,1))',1,[]);

[Sharen H]

thanks a lot

[Sharen H]

 secret = [22 33

33 44]

bi = dec2bin(secret,8) - '0';

out = reshape(mat2cell(bi,ones(size(bi,1),1),2*ones(size(bi,2)/2,1))',1,[]);

How to regroup the answer to get back the original secret