How to stop a rand function from getting the same result in a for loop

조회 수: 4 (최근 30일)
Cooper Mathews
Cooper Mathews 2020년 5월 2일
댓글: Mehmed Saad 2020년 5월 2일
Hey guys basic question.
I have this code here and i want to print the card deck in a random order:
for x = 1:52
y = randi([1 52]);
if y == 1
fprintf('%s\n','Spade Ace')
elseif y == 2
fprintf('%s\n','Spade 2')
(continues through the whole card deck 1-52)
elseif y == 51
fprintf('%s\n','Clubs Queen')
else
fprintf('%s\n','Clubs King')
end
end
Is there a way I can stop the rand function from comming up with the same number?

답변 (2개)

Walter Roberson
Walter Roberson 2020년 5월 2일
cards = {'Spade Ace', 'Spade 2', 'Spade 3' up to 'Clubs Queen', 'Clubs King'};
x = randperm(52);
fprintf('%s\n', cards{x});
No loop needed. rand() not explicitly used (it is used inside of randperm)

Mehmed Saad
Mehmed Saad 2020년 5월 2일
편집: Mehmed Saad 2020년 5월 2일
I dont know how to stop rand function from comming up with same number but there is a way you can do that by indexing and removing numbers.
z = 1:52;
x = zeros(1,52);
for i =1:52
y = randi([1 length(z)]);%
x(i) = z(y);
z(y) = [];
end
This will generate random number without repeating them
I stored all the values in x, to check if they are right type following in command window
sort(x)
it will be from 1:52 without any repeatition

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