how to vector with the same length of matrix

조회 수: 2 (최근 30일)
Valerio Gianforte
Valerio Gianforte 2020년 5월 1일
답변: Peter Perkins 2020년 5월 5일
Hi everyone,
I have to do a vector with the same lenght of matrix. This new vector should contain a package of hour from 1 to 8766, one time that it arrives to end point (8766) it must restarts from 1 and arrives to 8766 and this for the all length of the matrix. I hope to have been clear enough. Thank you.
File = 'D:\Valerio\data\Time_dir_Analysis\Analisys\data\a_ERA5.xlsx';
readFile = xlsread(File);
ERA5 = unique(readFile,'rows');
dt_ERA5 = datetime([ERA5(:,1:4) repmat([0 0],size(ERA5,1),1)]);
tt_ERA5 = timetable(dt_ERA5,ERA5(:,5:end));
  댓글 수: 1
Eva-Maria Weiss
Eva-Maria Weiss 2020년 5월 1일
I'm not sure, if I got the point. The problem is that size of Matrix is not devisible by 8766?
Maybe the mod function would help b = mod(a,m). Then you can create first your vector by means of repmat function as much as it 'fits'
(floor(size(Matrix,1)/8766))
into the matrix size and then concatenate the 'rest' as 1:b...

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채택된 답변

Ameer Hamza
Ameer Hamza 2020년 5월 1일
편집: Ameer Hamza 2020년 5월 1일
Try something like this
n = size(ERA5,1);
hours_vector = mod((1:n)-1,8766)+1;
hours_vector is like this
hours_vector = [1 2 3 .. .. 8765 8766 1 2 3 .. .. 8765 8766 ..]

추가 답변 (1개)

Peter Perkins
Peter Perkins 2020년 5월 5일
I'm going to suggest that you stay away from xlsread, and use readtable instead. Putting that together with Am eer's answer, you have
ERA5 = readtable('a_ERA5.xlsx');
ERA5.Time = datetime(ERA5{:,1:3}) + hours(ERA5.Var4);
ERA5 = table2timetable(ERA5(:,5:end));
n = height(ERA5);
ERA5.Hours = hours(mod((1:n)-1,8766)+1)';
head(ERA5)
ans =
8×6 timetable
Time Var5 Var6 Var7 Var8 Var9 Hours
____________________ _____ _____ ______ ______ ______ _____
01-Jan-2005 00:00:00 0.652 8.216 66.211 1.371 -1.466 1 hr
01-Jan-2005 01:00:00 0.645 8.029 65.466 0.559 -2.62 2 hr
01-Jan-2005 02:00:00 0.635 7.915 64.978 -0.359 -3.037 3 hr
01-Jan-2005 03:00:00 0.622 7.81 64.896 -0.861 -2.831 4 hr
01-Jan-2005 04:00:00 0.608 7.702 64.785 -0.94 -2.648 5 hr
01-Jan-2005 05:00:00 0.594 7.593 64.776 -1.396 -2.675 6 hr
01-Jan-2005 06:00:00 0.582 7.484 64.675 -1.944 -2.773 7 hr
01-Jan-2005 07:00:00 0.569 7.369 64.665 -2.103 -2.613 8 hr
I don't actually understand what you want to do with the vector of "hours", but perhaps something like that.

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