how to solve equations
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clc,clear
%Hourly variation of climatic parameter and various temperatures (July 13, 2004)
t = [9 10 11 12 1 2 3 4] % Time is in Hour
I(t) = [366 528 704 660 639 323 167 298] % intensity is in W\m2
Ta = [31 33 34 36 36 36 35 36] % ambient temperature at diffrent time
Ti = [34.2 35.1 37.7 38.2 38.7 37.8 37.4 37.7] % temperature of air at inlet at diffrent time
v = [2.83 3.9 4.3 4.83 4.47 4.8 3.63 3.83] % velocity of air in duct at diffrent time
% diffrent parameters for calculation
ho = 5.7+3.8*v;
hi = 2.8+3*v;
alpha_c = 0.9;
bita_c = 0.83;
tau_G = 0.95;
tau = 0.9;
alpha_T = 0.5;
%(alpha*tau)eff = 0.656;
ca = 1.005;
ma = 0.002;
hc = 7.98;
hr = 3.47;
Li = 0.05;
Lc = 0.0003;
LT = 0.0005;
LG = 0.003;
Lg = 0.003;
Ki = 0.035;
Kc = 0.039;
KT = 0.033;
KG = 1;
Kg = 0.04;
b = 0.45;
L = 1.2;
UT = KT\LT;
Ut = 1\[((LG\KG)+(1\(hc+hr))+(Lg\Kg)+(1\ho))];
Ub = 1\[((Li\Ki)+1\hi)];
UtT = 1\[((1\UT)+(1\Ut))];
Ut_air = 1\[((1\UtT)+(1\hT))];
UL = Ut_air+Ub;
hp1 = UT\(Ut+UT);
hp2 = hT\(UtT+hT);
To = (((hp1*hp2*0.656*I(t)\UL)+I(t))*(1-exp(-b*UL\ma*ca)*L))+Ti*exp{(-b*UL\ma*ca)*L};
i am trying to solve for To at diffrent given value of I(t) at diffrent time. then i want to plot like the image attached.
please help me with siple method because i am new to this software and my thesis evaluation is stayed for this. thanks in advance

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Star Strider
2020년 4월 28일
Your Question is not at all clear.
What equations do you want to solve, and for what variables?
답변 (1개)
Star Strider
2020년 4월 28일
There were a number of errors in your code, and some may still exist. I corrected the ones I was certain of.
In this (now vectorised) code, ‘To’ is an (8x8) matrix. Be certain that you are using the mldivide,\ function correctly, and that you do not intend rdivide,/, and specifically the vectorised (element-wise) version of rdivide (./) instead:
%Hourly variation of climatic parameter and various temperatures (July 13, 2004)
t = [9 10 11 12 1 2 3 4]; %Time is in Hour
I= [366 528 704 660 639 323 167 298]; %intensity is in W\m2
Ta = [31 33 34 36 36 36 35 36]; % ambient temperature at diffrent time
Ti = [34.2 35.1 37.7 38.2 38.7 37.8 37.4 37.7]; %temperature of air at inlet at diffrent time
v = [2.83 3.9 4.3 4.83 4.47 4.8 3.63 3.83]; %velocity of air in duct at diffrent time
%diffrent parameters for calculation
ho=5.7+3.8*v;
hi=2.8+3*v;
alpha_c= 0.9;
bita_c=0.83;
tau_G=0.95;
tau=0.9;
alpha_T= 0.5;
%(alpha*tau)eff= 0.656;
ca=1.005;
ma=0.002;
hc=7.98;
hr=3.47;
Li= 0.05;
Lc= 0.0003;
LT= 0.0005;
LG=0.003;
Lg=0.003;
Ki=0.035;
Kc=0.039;
KT=0.033;
KG=1;
Kg=0.04;
b=0.45;
L=1.2;
hT = 0.5;
UT=KT\LT;
Ut=1\[((LG\KG)+(1\(hc+hr))+(Lg\Kg)+(1\ho))];
Ub=1\[((Li\Ki)+1\hi)];
UtT=1\[((1\UT)+(1\Ut))];
Ut_air=1\[((1\UtT)+(1\hT))];
UL=Ut_air+Ub;
hp1=UT\(Ut+UT);
hp2= hT\(UtT+hT);
To= (((hp1.*hp2.*0.656.*I\UL)+I).*(1-exp(-b.*UL\ma.*ca).*L))+Ti.*exp((-b.*UL\ma.*ca).*L);
figure
plot(I, To)
grid
.
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