How to convert an image to binary matrix

I have an image P with dimension MxN. How to convert into dimension Mx8N ?

I have used P1 = dec2bin(P);

I am getting 65336x8 but I want 256x2048 how to do so ?

Answer 1

[Walter Roberson]

P1 = reshape( permute(reshape( (dec2bin(P, 8) - '0').', 8, size(P,1), size(P,2)), [2 1 3]), size(P,1), size(P,2)*8);

This preserves rows and expands each column to 8 columns -- so like

P(1,1)bit1 P(1,1)bit2 P(1,1)bit3 P(1,1)bit4 P(1,1)bit5 P(1,1)bit6 P(1,1)bit7 P(1,1)bit8 P(1,2)bit1 P(1,2)bit2 and so on

Another approach would be:

P1 = reshape( cat(3, bitget(P,8), bitget(P,7), bitget(P,6), bitget(P,5), bitget(P,4), bitget(P,3), bitget(P,2), bitget(P,1)), size(P,1), size(P,2)*8);

This preserves rows, and places all of the most significant bits together, then the second most significant, then the third most, and so on,

P(1,1)bit1 P(1,2)bit1 P(1,3)bit1 ... P(1,256)bit1 P(1,1)bit2 P(1,2)bit2 .. P(1,256)bit2 P(1,1)bit3 P(1,2)bit3 and so on

[Abhishek Bakhla]

thank you.

Answer 2

[KALYAN ACHARJYA]

>> ima=magic(3) % Lets suppose ima is a Image
ima =
     8     1     6
     3     5     7
     4     9     2
>> result=dec2bin(ima,8)
result =
  9×8 char array
    '00001000'
    '00000011'
    '00000100'
    '00000001'
    '00000101'
    '00001001'
    '00000110'
    '00000111'
    '00000010'
>> data2=cellstr(result)
data2 =
  9×1 cell array
    '00001000'
    '00000011'
    '00000100'
    '00000001'
    '00000101'
    '00001001'
    '00000110'
    '00000111'
    '00000010'
>> result3=reshape(data2,[3,3])
result3 =
  3×3 cell array
    '00001000'    '00000001'    '00000110'
    '00000011'    '00000101'    '00000111'
    '00000100'    '00001001'    '00000010'

#If you further go for cell to array, then '00000010' represents as 10 only, hence I showed with cell array

[Abhishek Bakhla]

thank you.

[MUHAMMAD ISLAM]

Brother you saved me <3