Multiple combinations of a matrix

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Ulika Naidoo
Ulika Naidoo 2020년 4월 24일
댓글: Ulika Naidoo 2020년 4월 25일
I have a matrix m, with 2 columns, M= [1, 2; 3, 4; 5, 6].
I need to the combinations of column one with its assocated column two entry.
For example:
x = [1, 2, 3, 4; 1, 2, 5, 6; 3, 4, 5, 6]
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Turlough Hughes
Turlough Hughes 2020년 4월 24일
Do you want to be able to do this generally for any number of rows?
Ulika Naidoo
Ulika Naidoo 2020년 4월 24일
Yes, for any number of rows please.

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Turlough Hughes
Turlough Hughes 2020년 4월 24일
편집: Turlough Hughes 2020년 4월 25일
Try the following, it should work for any size of M.
function x = pairCombos(M)
numRows = size(M,1);
C = combnk(1:numRows,2); % Lists every pair combination of row indicies.
x = zeros(size(C,1),size(M,2)*2); % Preallocate space for variable x.
for i = 1:size(C,1)
x(i,:) = [M(C(i,1),:) M(C(i,2),:)]; % generate x as requested.
end
end
The final order depends the output from the combnk function. You might also consider using the sortrows function afterwards.
  댓글 수: 5
Turlough Hughes
Turlough Hughes 2020년 4월 25일
What do you mean by take x and find combinations with m? Can you explain a bit more about what you're doing?
Ulika Naidoo
Ulika Naidoo 2020년 4월 25일
I'm trying to find the closest value from matrix M to a number L.
So where M = 1 2
3 4
5 6
and all combos so x = 1 2 3 4
1 2 5 6
3 4 5 6
But if I some column 1 and 3 then a= 4 6 8
However if any of these values from a are less than L, then to find combo's of X and M again and so on,
x1 = 1 2 3 4 1 2
1 2 5 6 1 2
3 4 5 6 1 2
1 2 3 4 3 4
1 2 5 6 3 4
3 4 5 6 3 4
I hope I made sense there. But then I realised I can just get combo's for X and X find the sum of column 1 and 3, if that is less than L , then sum 1, 3 and 5, if still less than L then finally sum 1, 3 , 5 and 7.
x2 =1 2 3 4 1 2 3 4
1 2 5 6 1 2 3 4
3 4 5 6 1 2 3 4
......
I was trying to find the optium number of batteries to use in a design with their associated costs, where L was the total voltage required, M column 1 was the volts and column 2 was the hours the batter can run for.
Thank you very much for your help!

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