Deviation between tfestimate+lsim and bode on same transfer function

조회 수: 5 (최근 30일)
Goal:
Create an input signal to find the frequency response of a physical system.
Process:
Since I have an idea/hypothesis of what the frequency response of this physical system looks like I made a dummy transfer function (double mass spring damper) on which I could test the desired input signal. From this transfer function I made two bode plots: one using the "bode" function and one using the "tfestimate" function (in combination with the "lsim" function and my input signal).
Problem:
The course of both plots is extremely similar in terms of magnitude and phase values however there is quite a big difference in the frequencies at which similar values occur.
I tried using white noise instead of the input signal I desired, which gave the same results.
Code:
%% Parameters for Transfer Function
m0 = 0.0;
k0 = 0;
m1 = 3.6; % Apperent stem mass at current robot position (not plant mass!) [kg]
m2 = 3.6; % Felt mass of the branch (+ the remaining stem influence) [kg]
b1 = 10; % Damping stem at current robot position [Ns/m]
b2 = 10; % Damping of the branch (+ the remaining stem influence) [Ns/m]
k1= 400; % Stiffness stem at current robot position [N/m]
k2 = 400; % Stiffness of the branch (+ the remaining stem influence) [N/m]
x1 = 0; %0.05; %Preloading of stem spring [m]
%% Analytical TF (double mass spring damper)
num = [m2, b2, k2];
den = [(m0+m1)*m2, (m0+m1)*b2+m2*b1+m2*b2, m2*k2+(m0+m1)*k2+m2*(k0+k1)+b1*b2 b1*k2+b2*(k0+k1), (k0+k1)*k2];
transfer = tf(num,den);
figure()
bode(transfer)
%% Input signal TF's
Fs = 100;
Ts = 1/Fs;
t = 60;
time = 0:Ts:t-Ts;
% white noise
in = wgn(length(time),1,10);
% % Frequency sweep (desired signal)
% bias = 0.0;
% f0 = 0.0; %% Initial frequency (Hz)
% f1 = 10.0; %% End frequency (Hz)
% Amp0 =25.0; %% Initial amplitude (mm)
% Amp1 = 5.0; %% End amplitude (mm)
% target_time = 60.0; %% Time in which to get from initial to final frequency (sec)
% k = (f1-f0)/target_time; %% The frequency change rate (Hz/s)
% l = (Amp0-Amp1)/target_time; %% The amplitude change rate (mm/s)
% for t=1:length(time)
% in(t) = (Amp0-l*time(t))*sin(2*pi*((k*time(t))/2+f0)*time(t)) + bias;
% end
%% TF simulation
out = lsim(transfer, in, time);
% Enhancing spectral estimation for bode
res = 0.1;
nfft = Fs/res;
window = hann(nfft);
noverlap = nfft/2;
[H,hz] = tfestimate(in, out,window,noverlap,nfft,Fs);
% Bode
figure()
subplot(2,1,1)
semilogx(hz,mag2db(abs(H)))
title('Bode plot from white noise + lsim + tfestimate')
ylabel('Amplitude [dB]')
grid
subplot(2,1,2)
semilogx(hz,rad2deg(angle(H)))
ylabel('Phase [deg]')
xlabel('Frequency [rad/s]');
grid
  댓글 수: 4
Ameer Hamza
Ameer Hamza 2020년 4월 24일
Lars, there is no need to close the question. I think that the discussion you added in the comment is quite useful and will be helpful for others searching for a similar question. I recommend that you add this discussion in an answer and accept your own answer.
Lars Janssen
Lars Janssen 2020년 4월 24일
Will do! Thanks again for the help, it's truly appreciated!

댓글을 달려면 로그인하십시오.

채택된 답변

Lars Janssen
Lars Janssen 2020년 4월 24일
For anybody else who finds this thread, the following has happened: when using "tfestimate" the unit in which the frequency is outputted can change based on the input that is given. Here you can find that if you use [txy,w] = tfestimate(___) the "w" variable will be in rad/sample, however when you use [txy,f] = tfestimate(___,fs) then the "f" variable will be in cycles/unit time, where fs specifies the unit time.
I solved this problem by simply multiplying "f" with 2*pi, but you can also get rid of the "fs" parameter in the "tfestimate" function and multiply "w" by "fs" to get the same result.

추가 답변 (0개)

카테고리

Help CenterFile Exchange에서 Signal Radiation and Collection에 대해 자세히 알아보기

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by