I have used the code below to plot a stacked plot,
X = [4 3 2 1];
x = X';
Y = [2 3 4 5; 3 4 5 6];
y = Y';
plot1=stackedplot(x,y)
The returned plot has a x-direction from min value to max value, how can I modify the code to make it from max to min as the X data presented?

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Ameer Hamza
Ameer Hamza 2020년 4월 22일
편집: Ameer Hamza 2020년 4월 22일

0 개 추천

stackedplot is still very limited in capabilities and does not support several features. Manipulating the appearance of X-axis is one of them. Currently, your best bet is to use subplots with few modifications to make it look like stackedplot.
X = [4 3 2 1];
x = X';
Y = [2 3 4 5; 3 4 5 6];
y = Y';
% plot1=stackedplot(x,y)
ax1 = subplot(2,1,1);
plot(x, y(:,1));
ax1.XAxis.Visible = 'off';
ax1.Position(2) = ax1.Position(2)-0.05;
ax1.XDir = 'reverse';
ax2 = subplot(2,1,2);
plot(x, y(:,2));
ax2.Position(2) = ax2.Position(2)+0.05;
ax2.XDir = 'reverse';

추가 답변 (2개)

Adam Danz
Adam Danz 2020년 11월 19일
편집: Adam Danz 2020년 11월 24일
You can get the axis handles in stackedplot using the undocumented NodeChildren property.
x = [4 3 2 1];
y = [2 3 4 5; 3 4 5 6]';
h = stackedplot(x,y);
set(findobj(h.NodeChildren,'Type','Axes'),'XDir','reverse')
Fangjun Jiang
Fangjun Jiang 2020년 4월 22일

0 개 추천

This is interesting. I wonder if this meets your need.
%%
x=1:4;
y=rand(size(x));
plot(y,x);
xlabel('y');
ylabel('x');
axis ij
view(90,-90);

댓글 수: 1

Error using view (line 63)
Using view with stackedplot is not supported.

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