find two minimum values not followed by each other.

조회 수: 2 (최근 30일)
FV
FV 2020년 4월 19일
댓글: Ameer Hamza 2020년 4월 20일
I am using mink(A,2) to find the two smallest values, but I need to find the two smallest values not followed by each other. How can this be done?
To illustrate: A(1; 1.2; 1.2; 0.7; 0.6; 0.61; 1; 1; 1.2;0.65) I want to find 0.6 and 0.65 and not 0.6 and 0.61.
  댓글 수: 1
FV
FV 2020년 4월 19일
I also need to find the index of the values.

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채택된 답변

Ameer Hamza
Ameer Hamza 2020년 4월 19일
편집: Ameer Hamza 2020년 4월 20일
Try this. It also preserve the order of minumum values
A = [0.65;1.2;1.2;0.7;0.6;0.61;1;1;1.2;1];
[vals,idx] = mink(A,3);
if diff(idx(1:2))==1
I = sort(idx([1 3]));
min_vals = A(I);
else
I = sort(idx([1 3]));
min_vals = A(I);
end
Result:
I =
1
5
min_vals =
0.6500
0.6000
  댓글 수: 2
FV
FV 2020년 4월 20일
Looks good, How can I get the index of the result?
Ameer Hamza
Ameer Hamza 2020년 4월 20일
See the updated code.

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추가 답변 (2개)

Mehmed Saad
Mehmed Saad 2020년 4월 19일
편집: Mehmed Saad 2020년 4월 19일
The long Method
A=[1;1.2;1.2;0.7;0.6;0.61;1;1;1.2;0.65];
miny = [];
for i =1:3
x = min(A);
A(A==x) = [];
if(i~=2)
miny = [miny x];
end
end
miny
The short one
A=[1;1.2;1.2;0.7;0.6;0.61;1;1;1.2;0.65];
B = sort(A);
miny = [B(1) B(3)]
  댓글 수: 3
Image Analyst
Image Analyst 2020년 4월 19일
So the long method is too long, but the short method is too short. Exactly how many lines of code do you want?
FV
FV 2020년 4월 19일
I don't want to sort it and therefore the short one doesn't work. I also need it to work for other A's.

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Image Analyst
Image Analyst 2020년 4월 19일
Try this:
A=[1;1.2;1.2;0.7;0.6;0.61;1;1;1.2;0.65];
% Plot, just for fun.
plot(A, 'r.-', 'MarkerSize', 30);
grid on;
% Find the values in ascending order, so the min value will be at location/index = 1.
[sortedA, sortOrder] = sort(A, 'Ascend')
% Now find the second lowest value but it can't be in the location next to the lowest value.
% Use diff() to see how many indexes the values are separated by each other by.
d = diff(sortOrder) % Don't want 1's
% Get min1 and min2 according to the non-consecutive criteria.
min1 = sortedA(1)
if d(1) ~= 1
% Not consecutive so we're OK.
min2 = sortedA(2) % Get the next one
else
% Consecutive so pick the next location with the next lowest value.
min2 = sortedA(3)
end
If it's homework, don't turn in my work as your own or you could get into trouble with your instructor.
  댓글 수: 1
FV
FV 2020년 4월 19일
This code also just work for this problem. Sometimes it's no smaller values beside the smallest one.
This is not a homework.

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